Question Simulator

O Level Biology (5090)

Biotechnology & genetic modification Banker

31 questions · about 2% of the marks we indexed · examined in 9 of 9 sessions.

Questions by year

2026

  • 2026 May/June · Paper 11 · Q401 markGenetic modification
  • 2026 May/June · Paper 12 · Q381 markMicroorganisms in biotechnology & fermenters
  • 2026 May/June · Paper 22 · Q8 (a(i), a(ii), b(i), b(ii))8 marksGenetic modification

2025

  • 2025 Oct/Nov · Paper 11 · Q341 markGenetic modification
  • 2025 Oct/Nov · Paper 11 · Q361 markMicroorganisms in biotechnology & fermenters
  • 2025 Oct/Nov · Paper 12 · Q351 markMicroorganisms in biotechnology & fermenters
  • 2025 Oct/Nov · Paper 12 · Q361 markGenetic modification
  • 2025 Oct/Nov · Paper 21 · Q6 (b)2 marksMicroorganisms in biotechnology & fermenters
  • 2025 May/June · Paper 21 · Q8 (a, b)10 marksMicroorganisms in biotechnology & fermenters
  • 2025 May/June · Paper 22 · Q5 (b(iii))1 markMicroorganisms in biotechnology & fermenters

2024

  • 2024 Oct/Nov · Paper 11 · Q361 markGenetic modification
  • 2024 Oct/Nov · Paper 12 · Q361 markMicroorganisms in biotechnology & fermenters
  • 2024 Oct/Nov · Paper 22 · Q6 (b(i), b(ii))6 marksGenetic modification
  • 2024 May/June · Paper 11 · Q361 markOfficial paper ↗Genetic modification
  • 2024 May/June · Paper 12 · Q361 markMicroorganisms in biotechnology & fermenters
  • 2024 May/June · Paper 21 · Q5 (a(iii), b(i), b(ii), b(iii), b(iv), b(v))9 marksOfficial paper ↗Genetic modification · Microorganisms in biotechnology & fermenters

2023

  • 2023 Oct/Nov · Paper 11 · Q361 markMicroorganisms in biotechnology & fermenters
  • 2023 Oct/Nov · Paper 22 · Q5 (a(i), c)3 marksGenetic modification · Microorganisms in biotechnology & fermenters
  • 2023 May/June · Paper 11 · Q361 markMicroorganisms in biotechnology & fermenters
  • 2023 May/June · Paper 12 · Q361 markMicroorganisms in biotechnology & fermenters
  • 2023 May/June · Paper 22 · Q7 (b)5 marksGenetic modification

2022

  • 2022 Oct/Nov · Paper 11 · Q291 markMicroorganisms in biotechnology & fermenters
  • 2022 Oct/Nov · Paper 11 · Q401 markGenetic modification
  • 2022 Oct/Nov · Paper 12 · Q291 markMicroorganisms in biotechnology & fermenters
  • 2022 Oct/Nov · Paper 12 · Q401 markGenetic modification
  • 2022 Oct/Nov · Paper 21 · Q2 (d(ii), d(iii))3 marksMicroorganisms in biotechnology & fermenters
  • 2022 Oct/Nov · Paper 22 · Q3 (a(i), a(iii), a(iv))4 marksMicroorganisms in biotechnology & fermenters
  • 2022 May/June · Paper 11 · Q291 markMicroorganisms in biotechnology & fermenters
  • 2022 May/June · Paper 11 · Q401 markGenetic modification
  • 2022 May/June · Paper 12 · Q291 markMicroorganisms in biotechnology & fermenters
  • 2022 May/June · Paper 12 · Q401 markGenetic modification

References only, not question text. Open Official paper ↗ where Cambridge publishes the paper, or see the official Cambridge past-papers page; for other papers, ask your school. “Paper 42” means Paper 4, variant 2.

Practice questions

Original questions written by HomiLabs in the style of the exam, with answers and mark schemes. They are not Cambridge past paper questions and have not been reviewed by Cambridge. Try each one before opening the answer.

Q1Microorganisms in biotechnology & fermenters · Core · Paper 1 style · 1 mark
  1. (a) Why does bread dough rise when yeast is added and the dough is left in a warm place? [1]
Show answer
  1. (a) B Yeast respires and produces carbon dioxide, which forms bubbles in the dough.
    Yeast respires the sugars in the dough, releasing carbon dioxide gas that is trapped as bubbles. Ethanol (A) is made but it evaporates during baking and does not make the dough rise.
Q2Microorganisms in biotechnology & fermenters · Core · Paper 1 style · 1 mark
  1. (a) Which enzyme is added to crushed fruit to increase the volume of juice extracted? [1]
Show answer
  1. (a) C pectinase
    Pectinase breaks down pectin in plant cell walls, so the cells release more juice and the juice is clearer. Amylase (A) digests starch, not the cell wall material that holds juice in.
Q3Microorganisms in biotechnology & fermenters · Core · Paper 2 style · 3 marks
  1. (a) State three reasons why bacteria are useful in biotechnology and genetic modification. [3]
Show answer
  1. (a) Any three of: they reproduce rapidly; they can make complex molecules; there are few ethical concerns about growing them; they contain plasmids; they share the same genetic code as other organisms.
    1 mark each for any three
Q4Microorganisms in biotechnology & fermenters · Core · Paper 2 style · 4 marks
  1. (a) Explain why bread dough containing yeast is left in a warm place before baking. [2]
  2. (b) State what happens to the yeast and the ethanol when the bread is baked. [2]
Show answer
  1. (a) Warmth gives a temperature near the optimum for yeast enzymes; so yeast respires faster and produces more carbon dioxide, making the dough rise faster.
    B1 enzymes near optimum temperature; B1 faster respiration/more CO₂
  2. (b) The yeast is killed by the high temperature; the ethanol evaporates.
    1 mark each
Q5Microorganisms in biotechnology & fermenters · Core · Paper 4 style · 6 marks

A student boiled some glucose solution, let it cool to 35 °C, then added yeast. A layer of vegetable oil was poured on top. A delivery tube led from the flask into a test tube of limewater.

  1. (a) Explain why the glucose solution was boiled and then cooled before the yeast was added. [2]
  2. (b) Explain why a layer of oil was poured onto the surface of the mixture. [1]
  3. (c) State what the limewater shows and the change you would see. [2]
  4. (d) Suggest how the student could measure the rate of respiration. [1]
Show answer
  1. (a) Boiling removes dissolved oxygen (and kills other microorganisms); cooling prevents the yeast being killed/its enzymes denatured by heat.
    B1 removes oxygen/sterilises; B1 cooled so yeast not killed
  2. (b) To stop oxygen from the air dissolving in the mixture, so respiration is anaerobic.
    B1
  3. (c) Carbon dioxide is produced; limewater turns milky/cloudy.
    1 mark each
  4. (d) Count the number of bubbles entering the limewater per minute.
    B1
Q6Microorganisms in biotechnology & fermenters · Core · Paper 2 style · 3 marks
  1. (a) Name the type of microorganism used to produce penicillin. [1]
  2. (b) State one other product made on a large scale in fermenters. [1]
  3. (c) State why penicillin is useful in medicine. [1]
Show answer
  1. (a) A fungus (Penicillium)
    B1
  2. (b) Human insulin (by GM bacteria) / ethanol / enzymes such as pectinase or lactase / mycoprotein.
    B1
  3. (c) It is an antibiotic that kills (or stops the growth of) bacteria.
    B1
Q7Microorganisms in biotechnology & fermenters · Standard · Paper 1 style · 1 mark
  1. (a) Lactose-free milk is made by treating milk with an enzyme. Which row is correct? [1]
Show answer
  1. (a) A enzyme lactase; products glucose and galactose
    Lactase breaks lactose (milk sugar) into glucose and galactose. Glucose and fructose (B) are the products of sucrose digestion, not lactose.
Q8Microorganisms in biotechnology & fermenters · Standard · Paper 1 style · 1 mark
  1. (a) An industrial fermenter has a jacket of cold water flowing around it. What is the main reason for this? [1]
Show answer
  1. (a) B to remove heat released by the respiring microorganisms and keep the optimum temperature
    Respiration by large numbers of microorganisms releases heat, which would denature their enzymes; the cold water jacket removes it. C is wrong because the jacket cools rather than heats.
Q9Microorganisms in biotechnology & fermenters · Standard · Paper 2 style · 5 marks

In a sugar mill in Sindh, molasses from sugar cane is mixed with water and yeast in large tanks to make ethanol for use as a biofuel.

  1. (a) Write the word equation for the anaerobic respiration of glucose by yeast. [2]
  2. (b) Explain why air is kept out of the fermenter. [2]
  3. (c) Suggest one advantage of using ethanol made from sugar cane as a fuel instead of petrol. [1]
Show answer
  1. (a) glucose → ethanol + carbon dioxide
    B1 ethanol; B1 carbon dioxide
  2. (b) Ethanol is only produced in anaerobic respiration; if oxygen is present, yeast respires aerobically and produces carbon dioxide and water instead of ethanol.
    B1 anaerobic respiration needed for ethanol; B1 with oxygen yeast respires aerobically (no ethanol)
  3. (c) It is a renewable fuel (sugar cane can be regrown) / reduces use of fossil fuels / the crop absorbs carbon dioxide as it grows.
    B1 any valid advantage
Q10Microorganisms in biotechnology & fermenters · Standard · Paper 2 style · 6 marks
  1. (a) Name the enzymes in a biological washing powder that remove: (i) a blood or egg stain; (ii) a cooking oil stain. [2]
  2. (b) Explain why biological washing powders work well at 30–40 °C. [2]
  3. (c) Explain why a biological washing powder is less effective in a 90 °C wash. [2]
Show answer
  1. (a) (i) protease; (ii) lipase
    1 mark each
  2. (b) The enzymes are near their optimum temperature; so they digest the stains quickly into small soluble molecules that wash away (saving energy compared with a hot wash).
    B1 near optimum temperature; B1 faster digestion of stains / soluble products wash out
  3. (c) At high temperature the enzymes are denatured; the active site changes shape so the stain molecules no longer fit.
    B1 denatured; B1 active site shape changed/substrate cannot bind
Q11Microorganisms in biotechnology & fermenters · Standard · Paper 2 style · 5 marks

A dairy in Lahore treats milk with lactase. Before treatment the milk contains 4.8 g of lactose per 100 cm³. After treatment it contains 0.3 g of lactose per 100 cm³.

  1. (a) Calculate the percentage of the lactose that was broken down. Give your answer to 3 significant figures. [2]
  2. (b) Explain why some people need to drink lactose-free milk. [2]
  3. (c) Suggest why lactose-free milk tastes sweeter than ordinary milk. [1]
Show answer
  1. (a) 93.8%
    M1 (4.8 − 0.3) ÷ 4.8 × 100; A1 93.8%
  2. (b) They do not make enough lactase (lactose intolerance); undigested lactose causes stomach pain, gas or diarrhoea.
    B1 little/no lactase produced; B1 symptoms from undigested lactose
  3. (c) Glucose and galactose taste sweeter than lactose.
    B1
Q12Microorganisms in biotechnology & fermenters · Standard · Paper 2 style · 6 marks
  1. (a) State four conditions that are monitored and controlled inside a fermenter used to produce penicillin, and give a reason for controlling each. [4]
  2. (b) Explain why the fermenter and nutrient medium are sterilised with steam before use. [2]
Show answer
  1. (a) Temperature – kept at the optimum for the fungus's enzymes; pH – kept at the optimum for enzymes; oxygen – supplied for aerobic respiration of the fungus; nutrients (glucose, ammonium/nitrogen source) – supplied for growth and energy; waste products removed – so they do not become toxic.
    1 mark each for any four conditions with reason
  2. (b) To kill any unwanted microorganisms; which would compete with the fungus for nutrients or contaminate/spoil the product.
    B1 kill other microorganisms; B1 competition / contamination of product
Q13Microorganisms in biotechnology & fermenters · Challenge · Paper 4 style · 8 marks

A student mixed 50 g of apple pulp with 2 cm³ of pectinase at different temperatures, then filtered for 20 minutes and measured the volume of juice. A control used boiled pectinase at 40 °C.Temperature / °C: 20, 30, 40, 50, 60Volume of juice / cm³: 8, 14, 21, 17, 6Control (boiled enzyme): 5 cm³

  1. (a) State the optimum temperature for pectinase in this experiment. [1]
  2. (b) Explain why a beaker of pulp with boiled pectinase was set up. [2]
  3. (c) Calculate the percentage increase in juice volume at 40 °C compared with the control. Give your answer to the nearest whole number. [2]
  4. (d) Explain why less juice was collected at 60 °C. [2]
  5. (e) Suggest how the student could find the optimum temperature more precisely. [1]
Show answer
  1. (a) 40 °C (from these results)
    B1
  2. (b) As a control; to show that the extra juice is due to the active enzyme (boiling denatures it).
    B1 control; B1 shows effect is due to active enzyme
  3. (c) 320%
    M1 (21 − 5) ÷ 5 × 100; A1 320%
  4. (d) Pectinase was denatured at the high temperature; so less pectin was broken down and fewer cells released juice.
    B1 enzyme denatured; B1 less pectin broken down
  5. (e) Repeat with smaller temperature intervals between 30 °C and 50 °C (e.g. every 2 °C).
    B1
Q14Microorganisms in biotechnology & fermenters · Challenge · Paper 2 style · 7 marks

The table shows changes in a penicillin fermenter.Time / hours: 0, 20, 40, 60, 80, 100, 120Fungal biomass / g per dm³: 1, 6, 14, 20, 21, 21, 20Penicillin / units per cm³: 0, 0, 2, 10, 22, 31, 35

  1. (a) Describe the changes in biomass of the fungus over the 120 hours. [2]
  2. (b) Calculate the mean rate of penicillin production, in units per cm³ per hour, between 60 and 100 hours. [2]
  3. (c) Suggest why most of the penicillin is produced after 60 hours. [2]
  4. (d) Suggest why the fermentation is stopped at about 120 hours. [1]
Show answer
  1. (a) Biomass increases quickly from 1 g/dm³ to 20 g/dm³ by 60 hours; then levels off at about 21 g/dm³ and falls slightly to 20 g/dm³ by 120 hours.
    B1 rapid increase then levels off; B1 data quoted with units
  2. (b) 0.525 units per cm³ per hour
    M1 (31 − 10) ÷ 40; A1 0.525
  3. (c) Penicillin is made mainly when growth of the fungus has slowed; this happens when nutrients such as glucose start to run out.
    B1 produced after main growth phase; B1 when nutrients become limiting
  4. (d) Penicillin production is slowing / nutrients are used up / the fungus is starting to die, so further time is not worth the cost.
    B1
Q15Microorganisms in biotechnology & fermenters · Challenge · Paper 2 style · 5 marks

A fermenter is started with 50 bacteria. In ideal conditions this species of bacterium divides once every 20 minutes.

  1. (a) Calculate how many bacteria would be present after 4 hours, assuming every cell divides every 20 minutes. [2]
  2. (b) Explain why the number of bacteria in a real fermenter does not keep increasing at this rate. [3]
Show answer
  1. (a) 204 800 bacteria
    M1 4 h = 12 divisions, 2¹² = 4096; A1 50 × 4096 = 204 800
  2. (b) Nutrients are used up; waste products (e.g. acids, toxins) build up and change pH; oxygen may become limiting/overcrowding; so the rate of division slows and some cells die.
    1 mark each for any three: nutrients run out; toxic waste builds up; pH changes; oxygen/space limiting; death rate rises
Q16Microorganisms in biotechnology & fermenters · Challenge · Paper 4 style · 8 marks

A student mixed 50 g of flour, 2 g of dried yeast and different masses of sugar with 30 cm³ of warm water. Each dough was pushed to the bottom of a measuring cylinder and the increase in volume was measured after 30 minutes.Mass of sugar / g: 0, 2, 4, 6, 8Increase in volume / cm³: 4, 12, 20, 24, 25

  1. (a) Describe the effect of sugar mass on the increase in dough volume. [2]
  2. (b) Calculate the mean rate of increase in volume, in cm³ per minute, for the dough with 4 g of sugar. Give your answer to 2 significant figures. [2]
  3. (c) Explain why the dough with no sugar still increased in volume a little. [1]
  4. (d) Suggest why increasing the sugar from 6 g to 8 g had little effect. [1]
  5. (e) Describe how the student could keep the temperature the same for all the cylinders. [1]
  6. (f) Suggest one improvement to make the results more reliable. [1]
Show answer
  1. (a) As the mass of sugar increases the volume increase rises, from 4 cm³ with no sugar to 24 cm³ at 6 g; above 6 g it levels off (25 cm³ at 8 g).
    B1 increases then levels off; B1 data quoted with units
  2. (b) 0.67 cm³ per minute
    M1 20 ÷ 30; A1 0.67
  3. (c) Yeast respired some sugars already in the flour (made from starch by amylase).
    B1
  4. (d) Sugar is no longer the limiting factor; another factor such as the amount of yeast or temperature limits the rate of respiration.
    B1
  5. (e) Stand all the cylinders in the same thermostatically controlled water bath (e.g. at 35 °C).
    B1
  6. (f) Repeat each sugar mass three times and calculate a mean.
    B1
Q17Microorganisms in biotechnology & fermenters · Challenge · Paper 2 style · 6 marks

A company grows genetically modified bacteria in a 10 000 dm³ fermenter. At the end of a batch the broth contains 1.2 g of insulin per dm³. Only 70% of this insulin is recovered when it is purified.

  1. (a) Calculate the mass of purified insulin, in kg, obtained from one batch. [2]
  2. (b) Explain why the contents of the fermenter are stirred continuously. [3]
  3. (c) Suggest why probes for pH and temperature are connected to a computer. [1]
Show answer
  1. (a) 8.4 kg
    M1 10 000 × 1.2 × 0.70 = 8400 g; A1 8.4 kg
  2. (b) Mixes nutrients so all bacteria can obtain them; spreads oxygen evenly for aerobic respiration; spreads heat evenly so there are no hot spots that denature enzymes; keeps bacteria suspended.
    1 mark each for any three
  3. (c) So that changes are detected quickly and corrected automatically, keeping conditions at the optimum.
    B1
Q18Genetic modification · Core · Paper 1 style · 1 mark
  1. (a) What is meant by genetic modification? [1]
Show answer
  1. (a) A changing the genetic material of an organism by removing, changing or inserting individual genes
    Genetic modification alters individual genes directly. B describes selective breeding, which works with whole organisms over many generations.
Q19Genetic modification · Core · Paper 2 style · 3 marks
  1. (a) Give three examples of genetic modification. [3]
Show answer
  1. (a) Any three of: bacteria producing human insulin; crop plants resistant to herbicides; crop plants resistant to insect pests; crops with added vitamins (e.g. rice containing β-carotene).
    1 mark each for any three
Q20Genetic modification · Core · Paper 2 style · 3 marks
  1. (a) State what is meant by a plasmid. [1]
  2. (b) State what is meant by a recombinant plasmid. [1]
  3. (c) Name the type of enzyme used to cut open a plasmid. [1]
Show answer
  1. (a) A small circle (loop) of DNA found in bacteria, separate from the main chromosome.
    B1
  2. (b) A plasmid that contains a gene from another organism inserted into it.
    B1
  3. (c) Restriction enzyme
    B1
Q21Genetic modification · Core · Paper 2 style · 3 marks

The steps below describe how bacteria are modified to make a human protein, but they are in the wrong order.P – The human gene is cut out using a restriction enzyme.Q – The modified bacteria multiply in a fermenter.R – The gene is joined into the plasmid using DNA ligase.S – A plasmid is cut open with the same restriction enzyme.T – The protein is extracted and purified.U – The recombinant plasmid is put into a bacterium.

  1. (a) Put steps P to U in the correct order, starting with P. [3]
Show answer
  1. (a) P, S, R, U, Q, T
    3 marks all correct; 2 marks one step out of place; 1 mark two steps out of place
Q22Genetic modification · Standard · Paper 1 style · 1 mark
  1. (a) In genetic modification, which enzyme joins a human gene into a bacterial plasmid? [1]
Show answer
  1. (a) B DNA ligase
    DNA ligase joins the sticky ends of the gene and plasmid together. Restriction enzymes (A) cut DNA; they do not join it.
Q23Genetic modification · Standard · Paper 2 style · 6 marks
  1. (a) Outline how bacteria can be genetically modified to produce human insulin. [6]
Show answer
  1. (a) The human insulin gene is cut out of human DNA using a restriction enzyme; this leaves sticky ends; a bacterial plasmid is cut with the same restriction enzyme; the gene is inserted into the plasmid and joined with DNA ligase; forming a recombinant plasmid; the plasmid is taken up by bacteria; the bacteria multiply in a fermenter and express the gene, making insulin which is extracted and purified.
    1 mark each for any six: restriction enzyme cuts out gene; sticky ends; plasmid cut with same enzyme; ligase joins; recombinant plasmid; inserted into bacteria; bacteria multiply/fermenter; gene expressed/insulin produced and purified
Q24Genetic modification · Standard · Paper 2 style · 3 marks
  1. (a) Explain why the same restriction enzyme must be used to cut both the human DNA and the plasmid. [2]
  2. (b) State what is meant by a sticky end. [1]
Show answer
  1. (a) It produces matching (complementary) sticky ends; so the bases on the gene and plasmid pair up and can be joined.
    B1 same/complementary sticky ends; B1 bases pair so they join
  2. (b) A short single-stranded length of DNA (unpaired bases) left at the end of a cut piece of DNA.
    B1
Q25Genetic modification · Standard · Paper 2 style · 3 marks
  1. (a) Explain how growing herbicide-resistant soya benefits a farmer. [2]
  2. (b) Suggest one risk of growing herbicide-resistant crops. [1]
Show answer
  1. (a) The farmer can spray herbicide over the whole field to kill weeds without killing the crop; so less competition for light, water and ions and a higher yield.
    B1 herbicide kills weeds not crop; B1 less competition → higher yield
  2. (b) The resistance gene could spread by pollen to wild relatives producing herbicide-resistant weeds (or more herbicide used, harming other plants and reducing biodiversity).
    B1
Q26Genetic modification · Standard · Paper 2 style · 4 marks
  1. (a) A student says: 'GM bacteria make human insulin because they have human DNA inside them.' Explain what else must happen for the bacterium to make insulin. [2]
  2. (b) Suggest why bacteria, rather than human cells, are used to produce insulin on a large scale. [2]
Show answer
  1. (a) The inserted gene must be expressed: the bacterium copies (transcribes) the gene and uses the code to join amino acids in the right order at its ribosomes, forming the insulin protein.
    B1 gene expressed/code read; B1 amino acids joined in correct sequence at ribosomes
  2. (b) Bacteria reproduce very rapidly, so large numbers are produced quickly; they are easy and cheap to grow in fermenters (few ethical concerns).
    B1 rapid reproduction; B1 cheap/easy to grow / no ethical concerns
Q27Genetic modification · Challenge · Paper 2 style · 8 marks

Cotton plants have been genetically modified to make a protein that is toxic to caterpillars which feed on them. Data from one cotton-growing district:Before GM cotton: 12 insecticide sprays per season; yield 1.9 tonnes per haAfter GM cotton: 5 insecticide sprays per season; yield 2.4 tonnes per ha

  1. (a) Calculate the percentage decrease in the number of sprays and the percentage increase in yield. Give your answers to 3 significant figures. [2]
  2. (b) Discuss the advantages and disadvantages of growing insect-resistant genetically modified crops. [6]
Show answer
  1. (a) Sprays: 58.3% decrease; yield: 26.3% increase
    M1 (12 − 5) ÷ 12 × 100 and (2.4 − 1.9) ÷ 1.9 × 100; A1 both
  2. (b) Advantages: less insecticide needed, saving money and reducing harm to farmers' health; fewer non-pest insects killed; higher yields/less crop damage, more food or income. Disadvantages: seeds may be expensive and must be bought each year; pests may evolve resistance to the toxin; genes may spread to wild relatives; reduced biodiversity if a single crop variety is grown widely; possible effects on non-target insects or on health not fully known.
    Max 4 for one side. 1 mark each for any six points across both sides: less insecticide; lower cost of spraying; safer for farmers/environment; higher yield; seed cost; pest resistance evolves; gene transfer to wild plants; reduced biodiversity; unknown long-term effects
Q28Genetic modification · Challenge · Paper 2 style · 5 marks
  1. (a) Explain why rice has been genetically modified to contain β-carotene. [2]
  2. (b) Suggest two concerns some people have about growing this rice. [2]
  3. (c) Suggest one alternative way of reducing vitamin A deficiency. [1]
Show answer
  1. (a) In some countries rice is the main food and people lack vitamin A; the body converts β-carotene into vitamin A, so the rice helps prevent vitamin A deficiency (which damages eyesight).
    B1 rice staple / diet lacks vitamin A; B1 β-carotene converted to vitamin A
  2. (b) Any two of: genes could transfer to wild rice varieties; farmers may depend on seed companies; effects on health not fully tested; reduced variety of crops grown; people may still lack other nutrients.
    1 mark each
  3. (c) Encourage eating a varied diet with vegetables such as carrots and green leafy vegetables / vitamin supplements.
    B1
Q29Genetic modification · Challenge · Paper 2 style · 6 marks
  1. (a) Before GM bacteria were used, insulin for people with diabetes was extracted from the pancreases of cattle and pigs. Explain the advantages of insulin produced by GM bacteria. [4]
  2. (b) Explain why a human gene can produce human insulin inside a bacterium. [2]
Show answer
  1. (a) It is identical to human insulin, so fewer allergic reactions/side effects; it can be produced in large quantities; it is cheaper/supply does not depend on slaughtered animals; it avoids ethical and religious objections (e.g. pig products for Muslims, cattle products for Hindus).
    1 mark each for any four
  2. (b) The genetic code is the same (universal) in all organisms; the bacterium reads the same base triplets and joins the same amino acids in the same order.
    B1 genetic code universal; B1 same amino acid sequence made
Q30Genetic modification · Challenge · Paper 2 style · 6 marks

A trial compared genetically modified insect-resistant maize with non-GM maize.Plants damaged by stem borer: GM field 3%; non-GM field 28%

  1. (a) Calculate the percentage reduction in plants damaged by the stem borer in the GM field compared with the non-GM field. Give your answer to 3 significant figures. [2]
  2. (b) Suggest why 3% of the GM plants were still damaged. [1]
  3. (c) Farmers are told to plant a strip of non-GM maize beside their GM maize. Explain how this slows down the evolution of resistance in the stem borer. [3]
Show answer
  1. (a) 89.3%
    M1 (28 − 3) ÷ 28 × 100; A1 89.3%
  2. (b) Some borers may be resistant to the toxin / some plants made less toxin / borers moved in from nearby non-GM plants.
    B1
  3. (c) Non-resistant borers survive on the non-GM maize; they mate with any rare resistant borers from the GM field; so the resistance allele is diluted / resistant borers do not only breed with each other, and the allele does not increase quickly in frequency.
    B1 non-resistant borers survive in strip; B1 mate with resistant ones; B1 frequency of resistance allele rises more slowly

Similar questions

Questions that test the same subtopic in different years, grouped so you can work on one skill at a time.

References only: find each question in its paper (official link where available, otherwise through your school).

Microorganisms in biotechnology & fermenters Banker19 questions · 9/9 sessions
Genetic modification Banker14 questions · 8/9 sessions

Subtopics

Our analysis of how often each subtopic was examined and how many marks it carried, 2022 to May/June 2026.

SubtopicMarks indexedSessions
Microorganisms in biotechnology & fermenters Banker409/9
Genetic modification Banker328/9

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