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Practice questions
Original questions written by HomiLabs in the style of the exam, with answers and mark schemes. They are not
Cambridge past paper questions and have not been reviewed by Cambridge. Try each one before opening the answer.
Q1Concentration & titration calculations · Core · Paper 1 style · 1 mark
(a)How many moles of sodium hydroxide are in 25.0 cm³ of 0.200 mol/dm³ aqueous sodium hydroxide?[1]
Show answer
(a) A 0.00500
moles = 0.200 × 25.0/1000 = 0.00500 mol. C forgets to convert cm³ to dm³.
Q2Concentration & titration calculations · Core · Paper 2 style · 3 marks
25.0 cm³ of aqueous sodium hydroxide is exactly neutralised by 20.00 cm³ of 0.100 mol/dm³ hydrochloric acid.NaOH + HCl → NaCl + H₂O
(a)Calculate the number of moles of hydrochloric acid used.[1]
(b)Calculate the concentration of the sodium hydroxide in mol/dm³.[2]
Q5Concentration & titration calculations · Standard · Paper 2 style · 4 marks
A student dilutes 25.0 cm³ of a brand of vinegar to 250 cm³ with distilled water. 25.0 cm³ of the diluted vinegar needs 21.60 cm³ of 0.100 mol/dm³ aqueous sodium hydroxide for neutralisation.CH₃COOH + NaOH → CH₃COONa + H₂O
(a)Calculate the concentration of ethanoic acid in the diluted vinegar.[2]
(b)Calculate the concentration of ethanoic acid in the original vinegar in mol/dm³ and in g/dm³. [Mr: CH₃COOH, 60][2]
Q6Concentration & titration calculations · Challenge · Paper 2 style · 5 marks
An antacid tablet of mass 0.500 g contains calcium carbonate. It is added to 50.0 cm³ of 0.500 mol/dm³ hydrochloric acid (an excess). When the reaction stops, the excess acid in the whole solution is titrated and needs 64.00 cm³ of 0.250 mol/dm³ aqueous sodium hydroxide.CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂; NaOH + HCl → NaCl + H₂O [Mr: CaCO₃, 100]
(a)Calculate the number of moles of hydrochloric acid added at the start.[1]
(b)Calculate the number of moles of hydrochloric acid left over (in excess).[1]
(c)Calculate the mass of calcium carbonate in the tablet.[2]
(d)Calculate the percentage by mass of calcium carbonate in the tablet.[1]
Q7Concentration & titration calculations · Challenge · Paper 2 style · 5 marks
1.40 g of the hydroxide of a Group I metal, MOH, is dissolved in water and made up to 250 cm³ in a volumetric flask. 25.0 cm³ of this solution is neutralised by 25.00 cm³ of 0.100 mol/dm³ hydrochloric acid.MOH + HCl → MCl + H₂O [Ar: H, 1; O, 16]
(a)Calculate the number of moles of MOH in 25.0 cm³ of the solution and in the 250 cm³ flask.[2]
(b)Calculate the relative formula mass of MOH.[1]
(c)Deduce the relative atomic mass of M and identify M.[2]
Show answer
(a) 0.00250 mol; 0.0250 mol
0.100 × 0.02500 = 0.00250 B1; × 10 = 0.0250 B1
(b) 56
1.40 ÷ 0.0250 = 56 B1
(c) 39; potassium
56 − 17 = 39 M1; potassium A1
Q8Moles & reacting masses · Core · Paper 1 style · 1 mark
(a)How many moles of carbon dioxide molecules are in 4.4 g of carbon dioxide? [Mr: CO₂, 44][1]
Show answer
(a) B 0.10
moles = mass ÷ Mr = 4.4 ÷ 44 = 0.10 mol. A is a factor of 10 too small.
Q9Moles & reacting masses · Core · Paper 2 style · 4 marks
In a lime kiln in Sindh, limestone (calcium carbonate) is heated strongly.CaCO₃ → CaO + CO₂ [Ar: C, 12; O, 16; Ca, 40]
(a)Calculate the number of moles of calcium carbonate in 25.0 g.[1]
(b)Calculate the mass of calcium oxide formed when 25.0 g of calcium carbonate is completely decomposed.[2]
Q12Moles & reacting masses · Challenge · Paper 2 style · 6 marks
4.20 g of the carbonate of a Group II metal M is heated until there is no further change in mass. 2.00 g of the metal oxide remains.MCO₃ → MO + CO₂ [Ar: C, 12; O, 16]
(a)Calculate the mass of carbon dioxide given off and the number of moles of carbon dioxide.[2]
(b)Deduce the relative formula mass of MCO₃.[1]
(c)Deduce the relative atomic mass of M and identify M.[2]
(d)Check your answer by calculating the expected mass of the oxide MO.[1]
Q16Formulae & equations (incl. ionic) · Standard · Paper 2 style · 5 marks
(a)Write the formula of ammonium phosphate, which contains NH₄⁺ and PO₄³⁻ ions.[1]
(b)Write the formula of iron(III) hydroxide.[1]
(c)Write the formula of calcium nitrate.[1]
(d)Calcium carbonate reacts with dilute nitric acid. Write a balanced symbol equation for the reaction.[2]
Show answer
(a) (NH₄)₃PO₄
B1
(b) Fe(OH)₃
B1
(c) Ca(NO₃)₂
B1
(d) CaCO₃ + 2HNO₃ → Ca(NO₃)₂ + H₂O + CO₂
B1 correct formulae; B1 balanced
Q17Formulae & equations (incl. ionic) · Challenge · Paper 2 style · 7 marks
(a)Zinc powder is added to copper(II) sulfate solution. Write the ionic equation, with state symbols, for the reaction.[2]
(b)Identify the spectator ion in (a).[1]
(c)Chlorine gas is bubbled into aqueous potassium bromide. Write the ionic equation.[2]
(d)Write the ionic equation for the reaction of any carbonate ion with dilute acid.[2]
Show answer
(a) Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
B1 correct species; B1 state symbols
(b) sulfate ion, SO₄²⁻
B1
(c) Cl₂ + 2Br⁻ → 2Cl⁻ + Br₂
B1 species; B1 balanced
(d) CO₃²⁻ + 2H⁺ → CO₂ + H₂O
B1 species; B1 balanced
Q18Gas volumes (molar volume) · Core · Paper 1 style · 1 mark
(a)What is the volume of 0.25 mol of oxygen gas at room temperature and pressure? [molar volume = 24 dm³ at r.t.p.][1]
Show answer
(a) B 6.0 dm³
V = 0.25 × 24 = 6.0 dm³. D divides 24 by 0.25 instead of multiplying.
Q19Gas volumes (molar volume) · Core · Paper 2 style · 3 marks
Mg + 2HCl → MgCl₂ + H₂ [Ar: Mg, 24; one mole of any gas occupies 24 dm³ at r.t.p.]
(a)Calculate the number of moles of magnesium in 0.48 g.[1]
(b)Calculate the volume of hydrogen, in cm³, formed at room temperature and pressure when 0.48 g of magnesium reacts with excess acid.[2]
Show answer
(a) 0.020 mol
0.48 ÷ 24 = 0.020 B1
(b) 480 cm³
moles H₂ = 0.020 M1; 0.020 × 24 000 = 480 cm³ A1
Q20Gas volumes (molar volume) · Standard · Paper 2 style · 4 marks
50 cm³ of methane from a Sui gas supply is burned completely in 150 cm³ of oxygen. All volumes are measured at room temperature and pressure.CH₄ + 2O₂ → CO₂ + 2H₂O
(a)Calculate the volume of oxygen that reacts with 50 cm³ of methane.[1]
(b)Calculate the volume of carbon dioxide formed.[1]
(c)Calculate the total volume of gas left at the end, measured at room temperature and pressure, and state what it contains.[2]
Show answer
(a) 100 cm³
1 : 2 by volume, 2 × 50 = 100 cm³ B1
(b) 50 cm³
1 : 1, 50 cm³ B1
(c) 100 cm³: 50 cm³ of carbon dioxide and 50 cm³ of unreacted oxygen (water is a liquid at r.t.p.)
Q21Gas volumes (molar volume) · Challenge · Paper 2 style · 6 marks
A hair-bleach solution contains hydrogen peroxide. 50.0 cm³ of the solution is completely decomposed using a little manganese(IV) oxide. 180 cm³ of oxygen is collected at room temperature and pressure.2H₂O₂ → 2H₂O + O₂
(a)Calculate the number of moles of oxygen produced.[1]
(b)Calculate the concentration of the hydrogen peroxide solution in mol/dm³.[3]
(c)Calculate the concentration in g/dm³. [Mr: H₂O₂, 34][1]
Q23Empirical & molecular formulae · Standard · Paper 2 style · 4 marks
(a)An oxide of iron found in a red soil sample from Balochistan contains 70.0% iron by mass. Calculate its empirical formula. [Ar: O, 16; Fe, 56][3]
(b)Deduce the oxidation number of iron in this oxide.[1]
Show answer
(a) Fe₂O₃
Fe 70.0 ÷ 56 = 1.25; O 30.0 ÷ 16 = 1.875 M1; ratio 1 : 1.5 M1; = 2 : 3, Fe₂O₃ A1
(b) +3
B1
Q24Empirical & molecular formulae · Standard · Paper 2 style · 4 marks
Washing soda is hydrated sodium carbonate, Na₂CO₃·xH₂O. 5.00 g of washing soda is heated until all the water of crystallisation is removed. 1.85 g of anhydrous sodium carbonate remains. [Mr: Na₂CO₃, 106; H₂O, 18]
(a)Calculate the mass of water lost.[1]
(b)Calculate the number of moles of anhydrous sodium carbonate and of water.[2]
(c)Deduce the value of x.[1]
Show answer
(a) 3.15 g
5.00 − 1.85 = 3.15 g B1
(b) Na₂CO₃: 0.0175 mol; H₂O: 0.175 mol
1.85 ÷ 106 = 0.0175 B1; 3.15 ÷ 18 = 0.175 B1
(c) 10
0.175 ÷ 0.0175 = 10 B1
Q25Empirical & molecular formulae · Challenge · Paper 2 style · 6 marks
Compound Z, found in vinegar, contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. [Ar: H, 1; C, 12; O, 16]
(a)Calculate the empirical formula of compound Z.[3]
(b)The relative molecular mass of Z is 60. Deduce its molecular formula.[2]
(c)Z turns blue litmus red and fizzes with sodium carbonate. Name Z.[1]
Show answer
(a) CH₂O
C 40.0 ÷ 12 = 3.33; H 6.7 ÷ 1 = 6.7; O 53.3 ÷ 16 = 3.33 M1; divide by smallest M1; 1 : 2 : 1, CH₂O A1
(b) C₂H₄O₂
Mr CH₂O = 30 M1; 60 ÷ 30 = 2, C₂H₄O₂ A1
(c) ethanoic acid
B1
Q26Percentage yield, purity & composition · Core · Paper 2 style · 4 marks
2Mg + O₂ → 2MgO [Ar: O, 16; Mg, 24]
(a)Calculate the maximum (theoretical) mass of magnesium oxide that 12.0 g of magnesium can form.[2]
(b)Only 17.0 g of magnesium oxide is collected. Calculate the percentage yield.[1]
(c)Suggest one reason why the yield is less than 100%.[1]
(c) Some magnesium oxide smoke escaped from the crucible / not all the magnesium reacted.
B1
Q27Percentage yield, purity & composition · Standard · Paper 2 style · 4 marks
A 5.00 g sample of limestone from a quarry near Margalla Hills is added to excess dilute hydrochloric acid. 1.08 dm³ of carbon dioxide is collected at room temperature and pressure. The impurities do not react with the acid.CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂ [Mr: CaCO₃, 100; molar volume 24 dm³ at r.t.p.]
(a)Calculate the number of moles of carbon dioxide produced.[1]
(b)Calculate the mass of calcium carbonate in the sample.[2]
(c)Calculate the percentage purity of the limestone.[1]
Show answer
(a) 0.045 mol
1.08 ÷ 24 = 0.0450 B1
(b) 4.50 g
moles CaCO₃ = 0.0450 M1; 0.0450 × 100 = 4.50 g A1
(c) 90.0%
4.50 ÷ 5.00 × 100 = 90.0% B1
Q28Percentage yield, purity & composition · Challenge · Paper 2 style · 6 marks
A farmer near Sahiwal compares three nitrogen fertilisers: ammonium nitrate NH₄NO₃ (Mr 80), ammonium sulfate (NH₄)₂SO₄ (Mr 132) and urea CO(NH₂)₂ (Mr 60). [Ar: N, 14]
(a)Calculate the percentage by mass of nitrogen in each fertiliser. Give answers to 3 significant figures.[3]
(b)A farmer needs 70 kg of nitrogen for a field. Calculate the mass of urea needed.[2]
(c)Suggest one reason, other than nitrogen content, why a farmer might choose ammonium sulfate.[1]