Question Simulator

O Level Chemistry (5070)

Stoichiometry Banker

189 questions · about 12% of the marks we indexed · examined in 9 of 9 sessions.

Questions by year

2026

  • 2026 May/June · Paper 11 · Q81 markEmpirical & molecular formulae
  • 2026 May/June · Paper 11 · Q91 markConcentration & titration calculations
  • 2026 May/June · Paper 11 · Q101 markPercentage yield, purity & composition
  • 2026 May/June · Paper 11 · Q111 markEmpirical & molecular formulae
  • 2026 May/June · Paper 12 · Q61 markEmpirical & molecular formulae
  • 2026 May/June · Paper 12 · Q71 markFormulae & equations (incl. ionic)
  • 2026 May/June · Paper 12 · Q81 markGas volumes (molar volume)
  • 2026 May/June · Paper 12 · Q91 markConcentration & titration calculations
  • 2026 May/June · Paper 21 · Q2 (a)3 marksGas volumes (molar volume)
  • 2026 May/June · Paper 21 · Q5 (c, f)6 marksMoles & reacting masses
  • 2026 May/June · Paper 22 · Q2 (a)3 marksGas volumes (molar volume)
  • 2026 May/June · Paper 22 · Q5 (c, f)6 marksMoles & reacting masses · Percentage yield, purity & composition
  • 2026 May/June · Paper 31 · Q1 (c(i))1 markConcentration & titration calculations
  • 2026 May/June · Paper 42 · Q2 (c(i))1 markConcentration & titration calculations

2025

  • 2025 Oct/Nov · Paper 11 · Q81 markFormulae & equations (incl. ionic)
  • 2025 Oct/Nov · Paper 11 · Q91 markConcentration & titration calculations
  • 2025 Oct/Nov · Paper 11 · Q101 markMoles & reacting masses
  • 2025 Oct/Nov · Paper 11 · Q111 markMoles & reacting masses
  • 2025 Oct/Nov · Paper 12 · Q71 markFormulae & equations (incl. ionic)
  • 2025 Oct/Nov · Paper 12 · Q81 markRelative masses (Ar, Mr)
  • 2025 Oct/Nov · Paper 12 · Q91 markGas volumes (molar volume)
  • 2025 Oct/Nov · Paper 12 · Q101 markPercentage yield, purity & composition
  • 2025 Oct/Nov · Paper 12 · Q211 markFormulae & equations (incl. ionic)
  • 2025 Oct/Nov · Paper 21 · Q3 (c)3 marksMoles & reacting masses
  • 2025 Oct/Nov · Paper 21 · Q5 (c)3 marksEmpirical & molecular formulae
  • 2025 Oct/Nov · Paper 21 · Q6 (b(i), b(ii))3 marksMoles & reacting masses
  • 2025 Oct/Nov · Paper 22 · Q1 (a(iii))1 markEmpirical & molecular formulae
  • 2025 Oct/Nov · Paper 22 · Q2 (c)2 marksRelative masses (Ar, Mr)
  • 2025 Oct/Nov · Paper 22 · Q3 (c)3 marksGas volumes (molar volume)
  • 2025 Oct/Nov · Paper 22 · Q5 (d)3 marksEmpirical & molecular formulae
  • 2025 Oct/Nov · Paper 22 · Q6 (b(i), b(ii), d)4 marksFormulae & equations (incl. ionic) · Moles & reacting masses
  • 2025 Oct/Nov · Paper 31 · Q1 (d, e)2 marksConcentration & titration calculations
  • 2025 Oct/Nov · Paper 41 · Q2 (d, e)2 marksConcentration & titration calculations
  • 2025 Oct/Nov · Paper 42 · Q2 (d, e)2 marksConcentration & titration calculations
  • 2025 May/June · Paper 11 · Q61 markMoles & reacting masses
  • 2025 May/June · Paper 11 · Q91 markFormulae & equations (incl. ionic)
  • 2025 May/June · Paper 11 · Q101 markFormulae & equations (incl. ionic)
  • 2025 May/June · Paper 11 · Q111 markRelative masses (Ar, Mr)
  • 2025 May/June · Paper 11 · Q121 markGas volumes (molar volume)
  • 2025 May/June · Paper 11 · Q131 markConcentration & titration calculations
  • 2025 May/June · Paper 12 · Q61 markRelative masses (Ar, Mr)
  • 2025 May/June · Paper 12 · Q91 markRelative masses (Ar, Mr)
  • 2025 May/June · Paper 12 · Q101 markGas volumes (molar volume)
  • 2025 May/June · Paper 12 · Q111 markPercentage yield, purity & composition
  • 2025 May/June · Paper 12 · Q301 markPercentage yield, purity & composition
  • 2025 May/June · Paper 21 · Q4 (c(i))3 marksMoles & reacting masses
  • 2025 May/June · Paper 21 · Q6 (b, e)5 marksEmpirical & molecular formulae · Moles & reacting masses
  • 2025 May/June · Paper 21 · Q7 (c)2 marksFormulae & equations (incl. ionic)
  • 2025 May/June · Paper 22 · Q4 (c(ii))3 marksGas volumes (molar volume)
  • 2025 May/June · Paper 22 · Q5 (a(i), b(ii))2 marksFormulae & equations (incl. ionic)
  • 2025 May/June · Paper 22 · Q6 (b, e)5 marksEmpirical & molecular formulae · Moles & reacting masses
  • 2025 May/June · Paper 22 · Q7 (d)2 marksFormulae & equations (incl. ionic)
  • 2025 May/June · Paper 31 · Q1 (c, d, e, f)4 marksConcentration & titration calculations · Moles & reacting masses
  • 2025 May/June · Paper 41 · Q2 (c, d, e, f)4 marksConcentration & titration calculations · Moles & reacting masses
  • 2025 May/June · Paper 42 · Q2 (c, d, e, f)4 marksConcentration & titration calculations · Moles & reacting masses

2024

  • 2024 Oct/Nov · Paper 11 · Q71 markFormulae & equations (incl. ionic)
  • 2024 Oct/Nov · Paper 11 · Q81 markRelative masses (Ar, Mr)
  • 2024 Oct/Nov · Paper 11 · Q91 markMoles & reacting masses
  • 2024 Oct/Nov · Paper 11 · Q101 markEmpirical & molecular formulae
  • 2024 Oct/Nov · Paper 11 · Q341 markMoles & reacting masses
  • 2024 Oct/Nov · Paper 12 · Q41 markRelative masses (Ar, Mr)
  • 2024 Oct/Nov · Paper 12 · Q71 markRelative masses (Ar, Mr)
  • 2024 Oct/Nov · Paper 12 · Q81 markRelative masses (Ar, Mr)
  • 2024 Oct/Nov · Paper 12 · Q91 markMoles & reacting masses
  • 2024 Oct/Nov · Paper 12 · Q101 markEmpirical & molecular formulae
  • 2024 Oct/Nov · Paper 12 · Q111 markPercentage yield, purity & composition
  • 2024 Oct/Nov · Paper 12 · Q311 markMoles & reacting masses
  • 2024 Oct/Nov · Paper 12 · Q381 markConcentration & titration calculations
  • 2024 Oct/Nov · Paper 21 · Q2 (f)2 marksFormulae & equations (incl. ionic)
  • 2024 Oct/Nov · Paper 21 · Q5 (c)3 marksConcentration & titration calculations
  • 2024 Oct/Nov · Paper 21 · Q6 (d)3 marksMoles & reacting masses
  • 2024 Oct/Nov · Paper 22 · Q2 (f)2 marksFormulae & equations (incl. ionic)
  • 2024 Oct/Nov · Paper 22 · Q5 (a, c)4 marksFormulae & equations (incl. ionic) · Gas volumes (molar volume)
  • 2024 Oct/Nov · Paper 22 · Q6 (e)3 marksMoles & reacting masses
  • 2024 Oct/Nov · Paper 31 · Q1 (d, e, f(i), f(ii))7 marksConcentration & titration calculations · Empirical & molecular formulae · Moles & reacting masses
  • 2024 Oct/Nov · Paper 41 · Q2 (d, e, f(i), f(ii))7 marksConcentration & titration calculations · Empirical & molecular formulae · Moles & reacting masses
  • 2024 Oct/Nov · Paper 42 · Q2 (d, e, f)7 marksConcentration & titration calculations
  • 2024 May/June · Paper 11 · Q61 markOfficial paper ↗Empirical & molecular formulae
  • 2024 May/June · Paper 11 · Q71 markOfficial paper ↗Relative masses (Ar, Mr)
  • 2024 May/June · Paper 11 · Q81 markOfficial paper ↗Moles & reacting masses
  • 2024 May/June · Paper 11 · Q91 markOfficial paper ↗Moles & reacting masses
  • 2024 May/June · Paper 11 · Q101 markOfficial paper ↗Gas volumes (molar volume)
  • 2024 May/June · Paper 11 · Q111 markOfficial paper ↗Concentration & titration calculations
  • 2024 May/June · Paper 12 · Q41 markRelative masses (Ar, Mr)
  • 2024 May/June · Paper 12 · Q71 markFormulae & equations (incl. ionic)
  • 2024 May/June · Paper 12 · Q81 markRelative masses (Ar, Mr)
  • 2024 May/June · Paper 12 · Q91 markConcentration & titration calculations
  • 2024 May/June · Paper 12 · Q101 markMoles & reacting masses
  • 2024 May/June · Paper 12 · Q171 markGas volumes (molar volume)
  • 2024 May/June · Paper 12 · Q311 markPercentage yield, purity & composition
  • 2024 May/June · Paper 21 · Q1 (e)1 markOfficial paper ↗Empirical & molecular formulae
  • 2024 May/June · Paper 21 · Q2 (a)2 marksOfficial paper ↗Formulae & equations (incl. ionic)
  • 2024 May/June · Paper 21 · Q3 (a)3 marksOfficial paper ↗Gas volumes (molar volume)
  • 2024 May/June · Paper 21 · Q5 (c, e)5 marksOfficial paper ↗Formulae & equations (incl. ionic) · Moles & reacting masses
  • 2024 May/June · Paper 21 · Q9 (c)3 marksOfficial paper ↗Empirical & molecular formulae
  • 2024 May/June · Paper 22 · Q1 (e)1 markEmpirical & molecular formulae
  • 2024 May/June · Paper 22 · Q2 (a)2 marksFormulae & equations (incl. ionic)
  • 2024 May/June · Paper 22 · Q3 (a)3 marksGas volumes (molar volume)
  • 2024 May/June · Paper 22 · Q5 (c, e)5 marksFormulae & equations (incl. ionic) · Moles & reacting masses
  • 2024 May/June · Paper 22 · Q9 (b)3 marksEmpirical & molecular formulae
  • 2024 May/June · Paper 41 · Q2 (a(iv))1 markOfficial paper ↗Formulae & equations (incl. ionic)

2023

  • 2023 Oct/Nov · Paper 11 · Q71 markFormulae & equations (incl. ionic)
  • 2023 Oct/Nov · Paper 11 · Q81 markGas volumes (molar volume)
  • 2023 Oct/Nov · Paper 11 · Q91 markMoles & reacting masses
  • 2023 Oct/Nov · Paper 11 · Q101 markPercentage yield, purity & composition
  • 2023 Oct/Nov · Paper 11 · Q111 markGas volumes (molar volume)
  • 2023 Oct/Nov · Paper 12 · Q61 markFormulae & equations (incl. ionic)
  • 2023 Oct/Nov · Paper 12 · Q71 markRelative masses (Ar, Mr)
  • 2023 Oct/Nov · Paper 12 · Q81 markGas volumes (molar volume)
  • 2023 Oct/Nov · Paper 12 · Q91 markGas volumes (molar volume)
  • 2023 Oct/Nov · Paper 12 · Q101 markPercentage yield, purity & composition
  • 2023 Oct/Nov · Paper 12 · Q111 markMoles & reacting masses
  • 2023 Oct/Nov · Paper 21 · Q2 (e)2 marksFormulae & equations (incl. ionic)
  • 2023 Oct/Nov · Paper 21 · Q3 (a)2 marksFormulae & equations (incl. ionic)
  • 2023 Oct/Nov · Paper 21 · Q7 (a, d)5 marksConcentration & titration calculations · Gas volumes (molar volume)
  • 2023 Oct/Nov · Paper 21 · Q9 (c)2 marksEmpirical & molecular formulae
  • 2023 Oct/Nov · Paper 22 · Q2 (c)2 marksFormulae & equations (incl. ionic)
  • 2023 Oct/Nov · Paper 22 · Q3 (a)2 marksFormulae & equations (incl. ionic)
  • 2023 Oct/Nov · Paper 22 · Q7 (a, c)5 marksConcentration & titration calculations · Gas volumes (molar volume)
  • 2023 Oct/Nov · Paper 22 · Q9 (c)2 marksEmpirical & molecular formulae
  • 2023 Oct/Nov · Paper 31 · Q1 (d)2 marksConcentration & titration calculations
  • 2023 Oct/Nov · Paper 41 · Q2 (e)2 marksConcentration & titration calculations
  • 2023 Oct/Nov · Paper 42 · Q2 (e)2 marksConcentration & titration calculations
  • 2023 May/June · Paper 11 · Q61 markFormulae & equations (incl. ionic)
  • 2023 May/June · Paper 11 · Q71 markPercentage yield, purity & composition
  • 2023 May/June · Paper 11 · Q81 markConcentration & titration calculations
  • 2023 May/June · Paper 11 · Q91 markEmpirical & molecular formulae
  • 2023 May/June · Paper 11 · Q101 markMoles & reacting masses
  • 2023 May/June · Paper 12 · Q71 markFormulae & equations (incl. ionic)
  • 2023 May/June · Paper 12 · Q81 markRelative masses (Ar, Mr)
  • 2023 May/June · Paper 12 · Q101 markRelative masses (Ar, Mr)
  • 2023 May/June · Paper 12 · Q111 markPercentage yield, purity & composition
  • 2023 May/June · Paper 12 · Q281 markFormulae & equations (incl. ionic)
  • 2023 May/June · Paper 12 · Q381 markConcentration & titration calculations
  • 2023 May/June · Paper 21 · Q4 (c, e)3 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition
  • 2023 May/June · Paper 21 · Q9 (a, b)4 marksFormulae & equations (incl. ionic) · Gas volumes (molar volume)
  • 2023 May/June · Paper 22 · Q3 (a(i))3 marksMoles & reacting masses
  • 2023 May/June · Paper 22 · Q4 (c, e)3 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition
  • 2023 May/June · Paper 22 · Q9 (a, b)4 marksFormulae & equations (incl. ionic) · Gas volumes (molar volume)
  • 2023 May/June · Paper 31 · Q1 (f, g, h)5 marksConcentration & titration calculations
  • 2023 May/June · Paper 41 · Q2 (d, e, f)5 marksConcentration & titration calculations
  • 2023 May/June · Paper 42 · Q2 (e, f, g)5 marksConcentration & titration calculations · Gas volumes (molar volume)

2022

  • 2022 Oct/Nov · Paper 11 · Q121 markFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 11 · Q131 markMoles & reacting masses
  • 2022 Oct/Nov · Paper 11 · Q141 markEmpirical & molecular formulae
  • 2022 Oct/Nov · Paper 11 · Q151 markGas volumes (molar volume)
  • 2022 Oct/Nov · Paper 11 · Q161 markPercentage yield, purity & composition
  • 2022 Oct/Nov · Paper 11 · Q281 markConcentration & titration calculations
  • 2022 Oct/Nov · Paper 12 · Q121 markFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 12 · Q131 markMoles & reacting masses
  • 2022 Oct/Nov · Paper 12 · Q141 markEmpirical & molecular formulae
  • 2022 Oct/Nov · Paper 12 · Q151 markConcentration & titration calculations
  • 2022 Oct/Nov · Paper 21 · Q3 (e(i), e(ii))3 marksEmpirical & molecular formulae
  • 2022 Oct/Nov · Paper 21 · Q4 (b, e)5 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition
  • 2022 Oct/Nov · Paper 21 · Q6 (b(i))2 marksFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 21 · Q8 (d)1 markFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 21 · Q9 (a(i))3 marksConcentration & titration calculations
  • 2022 Oct/Nov · Paper 22 · Q3 (e)2 marksEmpirical & molecular formulae
  • 2022 Oct/Nov · Paper 22 · Q4 (c, d)5 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition
  • 2022 Oct/Nov · Paper 22 · Q6 (c)2 marksFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 22 · Q8 (d)2 marksFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 22 · Q9 (a(i))3 marksConcentration & titration calculations
  • 2022 Oct/Nov · Paper 31 · Q1 (b, c, d, e)5 marksConcentration & titration calculations · Moles & reacting masses
  • 2022 Oct/Nov · Paper 41 · Q3 (a)1 markFormulae & equations (incl. ionic)
  • 2022 Oct/Nov · Paper 41 · Q5 (f, g, h, i, j)5 marksConcentration & titration calculations
  • 2022 Oct/Nov · Paper 42 · Q5 (f, g, h, i, j)5 marksConcentration & titration calculations
  • 2022 May/June · Paper 11 · Q121 markFormulae & equations (incl. ionic)
  • 2022 May/June · Paper 11 · Q131 markFormulae & equations (incl. ionic)
  • 2022 May/June · Paper 11 · Q141 markEmpirical & molecular formulae
  • 2022 May/June · Paper 11 · Q151 markMoles & reacting masses
  • 2022 May/June · Paper 11 · Q351 markMoles & reacting masses
  • 2022 May/June · Paper 12 · Q121 markFormulae & equations (incl. ionic)
  • 2022 May/June · Paper 12 · Q131 markRelative masses (Ar, Mr)
  • 2022 May/June · Paper 12 · Q141 markConcentration & titration calculations
  • 2022 May/June · Paper 12 · Q151 markMoles & reacting masses
  • 2022 May/June · Paper 12 · Q381 markEmpirical & molecular formulae
  • 2022 May/June · Paper 21 · Q2 (f)3 marksGas volumes (molar volume)
  • 2022 May/June · Paper 21 · Q5 (b(i), b(iii), b(iv))4 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition · Relative masses (Ar, Mr)
  • 2022 May/June · Paper 21 · Q7 (e)3 marksMoles & reacting masses
  • 2022 May/June · Paper 21 · Q8 (d(ii))3 marksEmpirical & molecular formulae
  • 2022 May/June · Paper 21 · Q9 (b(ii), d(ii))4 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition
  • 2022 May/June · Paper 22 · Q2 (e(i), f)4 marksFormulae & equations (incl. ionic) · Gas volumes (molar volume)
  • 2022 May/June · Paper 22 · Q6 (a, c)4 marksFormulae & equations (incl. ionic) · Relative masses (Ar, Mr)
  • 2022 May/June · Paper 22 · Q8 (d)3 marksMoles & reacting masses
  • 2022 May/June · Paper 22 · Q9 (d(ii))3 marksEmpirical & molecular formulae
  • 2022 May/June · Paper 22 · Q10 (a, b(iii))3 marksFormulae & equations (incl. ionic) · Percentage yield, purity & composition
  • 2022 May/June · Paper 31 · Q1 (b, c, d, e, f)6 marksConcentration & titration calculations · Formulae & equations (incl. ionic)
  • 2022 May/June · Paper 41 · Q4 (e, f, j, k, l, m(i))7 marksConcentration & titration calculations · Moles & reacting masses
  • 2022 May/June · Paper 42 · Q1 (c(i), c(ii), c(iii), c(iv))5 marksConcentration & titration calculations

References only, not question text. Open Official paper ↗ where Cambridge publishes the paper, or see the official Cambridge past-papers page; for other papers, ask your school. “Paper 42” means Paper 4, variant 2.

Practice questions

Original questions written by HomiLabs in the style of the exam, with answers and mark schemes. They are not Cambridge past paper questions and have not been reviewed by Cambridge. Try each one before opening the answer.

Q1Concentration & titration calculations · Core · Paper 1 style · 1 mark
  1. (a) How many moles of sodium hydroxide are in 25.0 cm³ of 0.200 mol/dm³ aqueous sodium hydroxide? [1]
Show answer
  1. (a) A 0.00500
    moles = 0.200 × 25.0/1000 = 0.00500 mol. C forgets to convert cm³ to dm³.
Q2Concentration & titration calculations · Core · Paper 2 style · 3 marks

25.0 cm³ of aqueous sodium hydroxide is exactly neutralised by 20.00 cm³ of 0.100 mol/dm³ hydrochloric acid.NaOH + HCl → NaCl + H₂O

  1. (a) Calculate the number of moles of hydrochloric acid used. [1]
  2. (b) Calculate the concentration of the sodium hydroxide in mol/dm³. [2]
Show answer
  1. (a) 0.00200 mol
    0.100 × 20.00/1000 = 0.00200 B1
  2. (b) 0.0800 mol/dm³
    moles NaOH = 0.00200 (1 : 1) M1; 0.00200 ÷ 0.0250 = 0.0800 A1
Q3Concentration & titration calculations · Standard · Paper 1 style · 1 mark
  1. (a) What is the concentration, in g/dm³, of 0.150 mol/dm³ aqueous sodium hydroxide? [Mr: NaOH, 40] [1]
Show answer
  1. (a) C 6.00 g/dm³
    g/dm³ = mol/dm³ × Mr = 0.150 × 40 = 6.00. B divides by 40 instead of multiplying.
Q4Concentration & titration calculations · Standard · Paper 2 style · 4 marks

25.0 cm³ of 0.120 mol/dm³ aqueous sodium hydroxide is neutralised by 18.75 cm³ of dilute sulfuric acid.2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

  1. (a) Calculate the number of moles of sodium hydroxide in 25.0 cm³. [1]
  2. (b) Calculate the concentration of the sulfuric acid in mol/dm³. [2]
  3. (c) Calculate the concentration of the sulfuric acid in g/dm³. [Mr: H₂SO₄, 98] [1]
Show answer
  1. (a) 0.00300 mol
    0.120 × 0.0250 = 0.00300 B1
  2. (b) 0.0800 mol/dm³
    moles H₂SO₄ = 0.00300 ÷ 2 = 0.00150 M1; 0.00150 ÷ 0.01875 = 0.0800 A1
  3. (c) 7.84 g/dm³
    0.0800 × 98 = 7.84 B1
Q5Concentration & titration calculations · Standard · Paper 2 style · 4 marks

A student dilutes 25.0 cm³ of a brand of vinegar to 250 cm³ with distilled water. 25.0 cm³ of the diluted vinegar needs 21.60 cm³ of 0.100 mol/dm³ aqueous sodium hydroxide for neutralisation.CH₃COOH + NaOH → CH₃COONa + H₂O

  1. (a) Calculate the concentration of ethanoic acid in the diluted vinegar. [2]
  2. (b) Calculate the concentration of ethanoic acid in the original vinegar in mol/dm³ and in g/dm³. [Mr: CH₃COOH, 60] [2]
Show answer
  1. (a) 0.0864 mol/dm³
    moles NaOH = 0.100 × 0.02160 = 0.00216 = moles acid M1; 0.00216 ÷ 0.0250 = 0.0864 A1
  2. (b) 0.864 mol/dm³; 51.8 g/dm³
    × 10 = 0.864 mol/dm³ B1; 0.864 × 60 = 51.8 g/dm³ B1
Q6Concentration & titration calculations · Challenge · Paper 2 style · 5 marks

An antacid tablet of mass 0.500 g contains calcium carbonate. It is added to 50.0 cm³ of 0.500 mol/dm³ hydrochloric acid (an excess). When the reaction stops, the excess acid in the whole solution is titrated and needs 64.00 cm³ of 0.250 mol/dm³ aqueous sodium hydroxide.CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂; NaOH + HCl → NaCl + H₂O [Mr: CaCO₃, 100]

  1. (a) Calculate the number of moles of hydrochloric acid added at the start. [1]
  2. (b) Calculate the number of moles of hydrochloric acid left over (in excess). [1]
  3. (c) Calculate the mass of calcium carbonate in the tablet. [2]
  4. (d) Calculate the percentage by mass of calcium carbonate in the tablet. [1]
Show answer
  1. (a) 0.0250 mol
    0.500 × 0.0500 = 0.0250 B1
  2. (b) 0.0160 mol
    0.250 × 0.06400 = 0.0160 B1
  3. (c) 0.450 g
    acid reacted = 0.0090 mol M1; CaCO₃ = 0.0045 mol × 100 = 0.450 g A1
  4. (d) 90.0%
    0.450 ÷ 0.500 × 100 = 90.0% B1
Q7Concentration & titration calculations · Challenge · Paper 2 style · 5 marks

1.40 g of the hydroxide of a Group I metal, MOH, is dissolved in water and made up to 250 cm³ in a volumetric flask. 25.0 cm³ of this solution is neutralised by 25.00 cm³ of 0.100 mol/dm³ hydrochloric acid.MOH + HCl → MCl + H₂O [Ar: H, 1; O, 16]

  1. (a) Calculate the number of moles of MOH in 25.0 cm³ of the solution and in the 250 cm³ flask. [2]
  2. (b) Calculate the relative formula mass of MOH. [1]
  3. (c) Deduce the relative atomic mass of M and identify M. [2]
Show answer
  1. (a) 0.00250 mol; 0.0250 mol
    0.100 × 0.02500 = 0.00250 B1; × 10 = 0.0250 B1
  2. (b) 56
    1.40 ÷ 0.0250 = 56 B1
  3. (c) 39; potassium
    56 − 17 = 39 M1; potassium A1
Q8Moles & reacting masses · Core · Paper 1 style · 1 mark
  1. (a) How many moles of carbon dioxide molecules are in 4.4 g of carbon dioxide? [Mr: CO₂, 44] [1]
Show answer
  1. (a) B 0.10
    moles = mass ÷ Mr = 4.4 ÷ 44 = 0.10 mol. A is a factor of 10 too small.
Q9Moles & reacting masses · Core · Paper 2 style · 4 marks

In a lime kiln in Sindh, limestone (calcium carbonate) is heated strongly.CaCO₃ → CaO + CO₂ [Ar: C, 12; O, 16; Ca, 40]

  1. (a) Calculate the number of moles of calcium carbonate in 25.0 g. [1]
  2. (b) Calculate the mass of calcium oxide formed when 25.0 g of calcium carbonate is completely decomposed. [2]
  3. (c) State one use of calcium oxide. [1]
Show answer
  1. (a) 0.250 mol
    25.0 ÷ 100 = 0.250 B1
  2. (b) 14.0 g
    moles CaO = 0.250 M1; 0.250 × 56 = 14.0 g A1
  3. (c) Neutralising acidic soil (or making cement / removing acidic gases)
    B1
Q10Moles & reacting masses · Standard · Paper 2 style · 5 marks

Fe₂O₃ + 3CO → 2Fe + 3CO₂ [Ar: C, 12; O, 16; Fe, 56]

  1. (a) Calculate the maximum mass of iron, in tonnes, that can be made from 8.0 tonnes of iron(III) oxide. [3]
  2. (b) Calculate the mass of carbon monoxide needed to react with 8.0 tonnes of iron(III) oxide. [2]
Show answer
  1. (a) 5.6 tonnes
    Mr Fe₂O₃ = 160 M1; 160 t gives 2 × 56 = 112 t of Fe M1; 8.0 × 112/160 = 5.6 t A1
  2. (b) 4.2 tonnes
    160 t Fe₂O₃ needs 3 × 28 = 84 t CO M1; 8.0 × 84/160 = 4.2 t A1
Q11Moles & reacting masses · Standard · Paper 2 style · 5 marks

2.4 g of magnesium is added to a solution containing 0.15 mol of hydrochloric acid.Mg + 2HCl → MgCl₂ + H₂ [Ar: Mg, 24; Cl, 35.5]

  1. (a) Calculate the number of moles of magnesium in 2.4 g. [1]
  2. (b) Show which reactant is in excess. [2]
  3. (c) Calculate the mass of magnesium chloride formed. [2]
Show answer
  1. (a) 0.10 mol
    2.4 ÷ 24 = 0.10 B1
  2. (b) Magnesium is in excess: 0.10 mol Mg needs 0.20 mol HCl, but only 0.15 mol HCl is present.
    M1 compare 0.10 mol Mg needing 0.20 mol HCl (or 0.15 mol HCl needs 0.075 mol Mg); A1 Mg in excess
  3. (c) 7.13 g (allow 7.1 g)
    moles MgCl₂ = 0.15 ÷ 2 = 0.075 M1; Mr MgCl₂ = 95; 0.075 × 95 = 7.125 = 7.13 g A1
Q12Moles & reacting masses · Challenge · Paper 2 style · 6 marks

4.20 g of the carbonate of a Group II metal M is heated until there is no further change in mass. 2.00 g of the metal oxide remains.MCO₃ → MO + CO₂ [Ar: C, 12; O, 16]

  1. (a) Calculate the mass of carbon dioxide given off and the number of moles of carbon dioxide. [2]
  2. (b) Deduce the relative formula mass of MCO₃. [1]
  3. (c) Deduce the relative atomic mass of M and identify M. [2]
  4. (d) Check your answer by calculating the expected mass of the oxide MO. [1]
Show answer
  1. (a) 2.20 g; 0.0500 mol
    4.20 − 2.00 = 2.20 g B1; 2.20 ÷ 44 = 0.0500 mol B1
  2. (b) 84
    moles MCO₃ = 0.0500, Mr = 4.20 ÷ 0.0500 = 84 B1
  3. (c) 24; magnesium
    Ar = 84 − (12 + 48) = 24 M1; magnesium A1
  4. (d) 2.00 g
    0.0500 × (24 + 16) = 2.00 g B1
Q13Formulae & equations (incl. ionic) · Core · Paper 1 style · 1 mark
  1. (a) What is the formula of aluminium sulfate? [1]
Show answer
  1. (a) D Al₂(SO₄)₃
    Al³⁺ and SO₄²⁻: two Al³⁺ (+6) balance three SO₄²⁻ (−6), so Al₂(SO₄)₃. C swaps the numbers.
Q14Formulae & equations (incl. ionic) · Core · Paper 2 style · 4 marks
  1. (a) Balance the equation for the reduction of iron(III) oxide in a blast furnace:…Fe₂O₃ + …CO → …Fe + …CO₂ [1]
  2. (b) Balance the equation for the complete combustion of propane, a gas in LPG cylinders:…C₃H₈ + …O₂ → …CO₂ + …H₂O [1]
  3. (c) Write the balanced equation, with state symbols, for the reaction of magnesium with dilute hydrochloric acid. [2]
Show answer
  1. (a) Fe₂O₃ + 3CO → 2Fe + 3CO₂
    B1
  2. (b) C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
    B1
  3. (c) Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
    B1 correct balanced formulae; B1 state symbols
Q15Formulae & equations (incl. ionic) · Standard · Paper 2 style · 6 marks
  1. (a) Write the ionic equation, with state symbols, for the neutralisation of any acid by any alkali. [2]
  2. (b) Aqueous silver nitrate is added to aqueous sodium chloride. Write the ionic equation, with state symbols, for the reaction. [2]
  3. (c) Aqueous barium chloride is added to aqueous sodium sulfate. Write the ionic equation and name the spectator ions. [2]
Show answer
  1. (a) H⁺(aq) + OH⁻(aq) → H₂O(l)
    B1 equation; B1 state symbols
  2. (b) Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
    B1 equation; B1 state symbols
  3. (c) Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s); spectator ions: Na⁺ and Cl⁻
    B1 equation; B1 both spectator ions
Q16Formulae & equations (incl. ionic) · Standard · Paper 2 style · 5 marks
  1. (a) Write the formula of ammonium phosphate, which contains NH₄⁺ and PO₄³⁻ ions. [1]
  2. (b) Write the formula of iron(III) hydroxide. [1]
  3. (c) Write the formula of calcium nitrate. [1]
  4. (d) Calcium carbonate reacts with dilute nitric acid. Write a balanced symbol equation for the reaction. [2]
Show answer
  1. (a) (NH₄)₃PO₄
    B1
  2. (b) Fe(OH)₃
    B1
  3. (c) Ca(NO₃)₂
    B1
  4. (d) CaCO₃ + 2HNO₃ → Ca(NO₃)₂ + H₂O + CO₂
    B1 correct formulae; B1 balanced
Q17Formulae & equations (incl. ionic) · Challenge · Paper 2 style · 7 marks
  1. (a) Zinc powder is added to copper(II) sulfate solution. Write the ionic equation, with state symbols, for the reaction. [2]
  2. (b) Identify the spectator ion in (a). [1]
  3. (c) Chlorine gas is bubbled into aqueous potassium bromide. Write the ionic equation. [2]
  4. (d) Write the ionic equation for the reaction of any carbonate ion with dilute acid. [2]
Show answer
  1. (a) Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
    B1 correct species; B1 state symbols
  2. (b) sulfate ion, SO₄²⁻
    B1
  3. (c) Cl₂ + 2Br⁻ → 2Cl⁻ + Br₂
    B1 species; B1 balanced
  4. (d) CO₃²⁻ + 2H⁺ → CO₂ + H₂O
    B1 species; B1 balanced
Q18Gas volumes (molar volume) · Core · Paper 1 style · 1 mark
  1. (a) What is the volume of 0.25 mol of oxygen gas at room temperature and pressure? [molar volume = 24 dm³ at r.t.p.] [1]
Show answer
  1. (a) B 6.0 dm³
    V = 0.25 × 24 = 6.0 dm³. D divides 24 by 0.25 instead of multiplying.
Q19Gas volumes (molar volume) · Core · Paper 2 style · 3 marks

Mg + 2HCl → MgCl₂ + H₂ [Ar: Mg, 24; one mole of any gas occupies 24 dm³ at r.t.p.]

  1. (a) Calculate the number of moles of magnesium in 0.48 g. [1]
  2. (b) Calculate the volume of hydrogen, in cm³, formed at room temperature and pressure when 0.48 g of magnesium reacts with excess acid. [2]
Show answer
  1. (a) 0.020 mol
    0.48 ÷ 24 = 0.020 B1
  2. (b) 480 cm³
    moles H₂ = 0.020 M1; 0.020 × 24 000 = 480 cm³ A1
Q20Gas volumes (molar volume) · Standard · Paper 2 style · 4 marks

50 cm³ of methane from a Sui gas supply is burned completely in 150 cm³ of oxygen. All volumes are measured at room temperature and pressure.CH₄ + 2O₂ → CO₂ + 2H₂O

  1. (a) Calculate the volume of oxygen that reacts with 50 cm³ of methane. [1]
  2. (b) Calculate the volume of carbon dioxide formed. [1]
  3. (c) Calculate the total volume of gas left at the end, measured at room temperature and pressure, and state what it contains. [2]
Show answer
  1. (a) 100 cm³
    1 : 2 by volume, 2 × 50 = 100 cm³ B1
  2. (b) 50 cm³
    1 : 1, 50 cm³ B1
  3. (c) 100 cm³: 50 cm³ of carbon dioxide and 50 cm³ of unreacted oxygen (water is a liquid at r.t.p.)
    M1 excess O₂ = 150 − 100 = 50 cm³; A1 total 100 cm³ (CO₂ + O₂)
Q21Gas volumes (molar volume) · Challenge · Paper 2 style · 6 marks

A hair-bleach solution contains hydrogen peroxide. 50.0 cm³ of the solution is completely decomposed using a little manganese(IV) oxide. 180 cm³ of oxygen is collected at room temperature and pressure.2H₂O₂ → 2H₂O + O₂

  1. (a) Calculate the number of moles of oxygen produced. [1]
  2. (b) Calculate the concentration of the hydrogen peroxide solution in mol/dm³. [3]
  3. (c) Calculate the concentration in g/dm³. [Mr: H₂O₂, 34] [1]
  4. (d) State the role of the manganese(IV) oxide. [1]
Show answer
  1. (a) 0.0075 mol
    180 ÷ 24 000 = 0.00750 mol B1
  2. (b) 0.30 mol/dm³
    moles H₂O₂ = 2 × 0.00750 = 0.0150 M1; volume 0.0500 dm³ M1; 0.0150 ÷ 0.0500 = 0.30 mol/dm³ A1
  3. (c) 10.2 g/dm³
    0.30 × 34 = 10.2 g/dm³ B1
  4. (d) catalyst
    B1
Q22Empirical & molecular formulae · Core · Paper 2 style · 3 marks

A sample of a hydrocarbon contains 2.4 g of carbon and 0.6 g of hydrogen. [Ar: H, 1; C, 12]

  1. (a) Calculate the empirical formula of the hydrocarbon. [2]
  2. (b) The relative molecular mass is 30. Deduce the molecular formula. [1]
Show answer
  1. (a) CH₃
    C: 2.4 ÷ 12 = 0.20; H: 0.6 ÷ 1 = 0.60 M1; ratio 1 : 3, CH₃ A1
  2. (b) C₂H₆
    Mr of CH₃ = 15, 30 ÷ 15 = 2 B1
Q23Empirical & molecular formulae · Standard · Paper 2 style · 4 marks
  1. (a) An oxide of iron found in a red soil sample from Balochistan contains 70.0% iron by mass. Calculate its empirical formula. [Ar: O, 16; Fe, 56] [3]
  2. (b) Deduce the oxidation number of iron in this oxide. [1]
Show answer
  1. (a) Fe₂O₃
    Fe 70.0 ÷ 56 = 1.25; O 30.0 ÷ 16 = 1.875 M1; ratio 1 : 1.5 M1; = 2 : 3, Fe₂O₃ A1
  2. (b) +3
    B1
Q24Empirical & molecular formulae · Standard · Paper 2 style · 4 marks

Washing soda is hydrated sodium carbonate, Na₂CO₃·xH₂O. 5.00 g of washing soda is heated until all the water of crystallisation is removed. 1.85 g of anhydrous sodium carbonate remains. [Mr: Na₂CO₃, 106; H₂O, 18]

  1. (a) Calculate the mass of water lost. [1]
  2. (b) Calculate the number of moles of anhydrous sodium carbonate and of water. [2]
  3. (c) Deduce the value of x. [1]
Show answer
  1. (a) 3.15 g
    5.00 − 1.85 = 3.15 g B1
  2. (b) Na₂CO₃: 0.0175 mol; H₂O: 0.175 mol
    1.85 ÷ 106 = 0.0175 B1; 3.15 ÷ 18 = 0.175 B1
  3. (c) 10
    0.175 ÷ 0.0175 = 10 B1
Q25Empirical & molecular formulae · Challenge · Paper 2 style · 6 marks

Compound Z, found in vinegar, contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. [Ar: H, 1; C, 12; O, 16]

  1. (a) Calculate the empirical formula of compound Z. [3]
  2. (b) The relative molecular mass of Z is 60. Deduce its molecular formula. [2]
  3. (c) Z turns blue litmus red and fizzes with sodium carbonate. Name Z. [1]
Show answer
  1. (a) CH₂O
    C 40.0 ÷ 12 = 3.33; H 6.7 ÷ 1 = 6.7; O 53.3 ÷ 16 = 3.33 M1; divide by smallest M1; 1 : 2 : 1, CH₂O A1
  2. (b) C₂H₄O₂
    Mr CH₂O = 30 M1; 60 ÷ 30 = 2, C₂H₄O₂ A1
  3. (c) ethanoic acid
    B1
Q26Percentage yield, purity & composition · Core · Paper 2 style · 4 marks

2Mg + O₂ → 2MgO [Ar: O, 16; Mg, 24]

  1. (a) Calculate the maximum (theoretical) mass of magnesium oxide that 12.0 g of magnesium can form. [2]
  2. (b) Only 17.0 g of magnesium oxide is collected. Calculate the percentage yield. [1]
  3. (c) Suggest one reason why the yield is less than 100%. [1]
Show answer
  1. (a) 20.0 g
    moles Mg = 12.0 ÷ 24 = 0.500 M1; 0.500 × 40 = 20.0 g A1
  2. (b) 85%
    17.0 ÷ 20.0 × 100 = 85% B1
  3. (c) Some magnesium oxide smoke escaped from the crucible / not all the magnesium reacted.
    B1
Q27Percentage yield, purity & composition · Standard · Paper 2 style · 4 marks

A 5.00 g sample of limestone from a quarry near Margalla Hills is added to excess dilute hydrochloric acid. 1.08 dm³ of carbon dioxide is collected at room temperature and pressure. The impurities do not react with the acid.CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂ [Mr: CaCO₃, 100; molar volume 24 dm³ at r.t.p.]

  1. (a) Calculate the number of moles of carbon dioxide produced. [1]
  2. (b) Calculate the mass of calcium carbonate in the sample. [2]
  3. (c) Calculate the percentage purity of the limestone. [1]
Show answer
  1. (a) 0.045 mol
    1.08 ÷ 24 = 0.0450 B1
  2. (b) 4.50 g
    moles CaCO₃ = 0.0450 M1; 0.0450 × 100 = 4.50 g A1
  3. (c) 90.0%
    4.50 ÷ 5.00 × 100 = 90.0% B1
Q28Percentage yield, purity & composition · Challenge · Paper 2 style · 6 marks

A farmer near Sahiwal compares three nitrogen fertilisers: ammonium nitrate NH₄NO₃ (Mr 80), ammonium sulfate (NH₄)₂SO₄ (Mr 132) and urea CO(NH₂)₂ (Mr 60). [Ar: N, 14]

  1. (a) Calculate the percentage by mass of nitrogen in each fertiliser. Give answers to 3 significant figures. [3]
  2. (b) A farmer needs 70 kg of nitrogen for a field. Calculate the mass of urea needed. [2]
  3. (c) Suggest one reason, other than nitrogen content, why a farmer might choose ammonium sulfate. [1]
Show answer
  1. (a) ammonium nitrate 35.0%; ammonium sulfate 21.2%; urea 46.7%
    NH₄NO₃: 28/80 × 100 = 35.0% B1; (NH₄)₂SO₄: 28/132 × 100 = 21.2% B1; CO(NH₂)₂: 28/60 × 100 = 46.7% B1
  2. (b) 150 kg
    70 ÷ 0.467 M1 = 150 kg A1 (70 × 60/28)
  3. (c) It also supplies sulfur / it may be cheaper / it is more readily available.
    B1 any sensible reason
Q29Relative masses (Ar, Mr) · Core · Paper 1 style · 1 mark
  1. (a) What is the relative formula mass, Mr, of hydrated copper(II) sulfate, CuSO₄·5H₂O? [Ar: H, 1; O, 16; S, 32; Cu, 64] [1]
Show answer
  1. (a) C 250
    64 + 32 + 4×16 + 5×18 = 160 + 90 = 250. A (160) is the anhydrous salt only.
Q30Relative masses (Ar, Mr) · Standard · Paper 2 style · 6 marks
  1. (a) Define relative atomic mass. [2]
  2. (b) A sample of chlorine contains 75% chlorine-35 and 25% chlorine-37 atoms. Calculate the relative atomic mass of chlorine. [2]
  3. (c) Calculate the relative formula mass of ammonium sulfate, (NH₄)₂SO₄, used as a fertiliser in Punjab. [Ar: H, 1; N, 14; O, 16; S, 32] [1]
  4. (d) Calculate the relative formula mass of calcium nitrate, Ca(NO₃)₂. [Ar: N, 14; O, 16; Ca, 40] [1]
Show answer
  1. (a) The average mass of the isotopes of an element (weighted by abundance) compared with 1/12 of the mass of a carbon-12 atom.
    B1 average/weighted mass of isotopes (atoms); B1 relative to 1/12 mass of ¹²C atom
  2. (b) 35.5
    (75 × 35 + 25 × 37) ÷ 100 M1 = 35.5 A1
  3. (c) 132
    2 × (14 + 4) + 32 + 64 = 132 B1
  4. (d) 164
    40 + 2 × (14 + 48) = 164 B1

Similar questions

Questions that test the same subtopic in different years, grouped so you can work on one skill at a time.

References only: find each question in its paper (official link where available, otherwise through your school).

Concentration & titration calculations Banker40 questions · 9/9 sessions
Moles & reacting masses Banker40 questions · 9/9 sessions
Formulae & equations (incl. ionic) Banker51 questions · 9/9 sessions
Gas volumes (molar volume) Banker25 questions · 9/9 sessions
Empirical & molecular formulae Banker28 questions · 9/9 sessions
Percentage yield, purity & composition Banker19 questions · 9/9 sessions
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Subtopics

Our analysis of how often each subtopic was examined and how many marks it carried, 2022 to May/June 2026.

SubtopicMarks indexedSessions
Concentration & titration calculations Banker1039/9
Moles & reacting masses Banker779/9
Formulae & equations (incl. ionic) Banker729/9
Gas volumes (molar volume) Banker519/9
Empirical & molecular formulae Banker499/9
Percentage yield, purity & composition Banker299/9
Relative masses (Ar, Mr) 207/9

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