References only, not question text. Open Official paper ↗ where Cambridge publishes the paper,
or see the official Cambridge past-papers page; for other papers, ask your
school. “Paper 42” means Paper 4, variant 2.
Practice questions
Original questions written by HomiLabs in the style of the exam, with answers and mark schemes. They are not
Cambridge past paper questions and have not been reviewed by Cambridge. Try each one before opening the answer.
Q1General wave properties · Core · Paper 2 style · 1 mark
(a)[1]
Show answer
(a) B 1.0 m/s
v = fλ = 4.0 × 0.25 = 1.0 m/s. D comes from dividing frequency by wavelength; A from dividing wavelength by frequency.
Q2General wave properties · Core · Paper 4 style · 6 marks
A student watches straight waves in a ripple tank. 15 waves pass a fixed point in 5.0 s. The distance between neighbouring crests is 2.4 cm.
(a)Calculate the frequency of the waves.[1]
(b)Calculate the speed of the waves.[2]
(c)Water waves are transverse. State the difference between a transverse wave and a longitudinal wave, and give one example of a longitudinal wave.[3]
Show answer
(a) 3.0 Hz
15 ÷ 5.0 = 3.0 Hz (B1)
(b) 7.2 cm/s
v = fλ (C1) = 3.0 × 2.4 = 7.2 cm/s (A1)
(c) transverse: vibrations perpendicular to the direction of energy transfer; longitudinal: vibrations parallel to the direction of energy transfer; example: sound (or P-waves)
B1 transverse description; B1 longitudinal description; B1 example
Q3General wave properties · Standard · Paper 4 style · 5 marks
Waves in a ripple tank have a frequency of 12 Hz. In the deep region their speed is 18 cm/s. They pass into a shallow region where their speed is 12 cm/s.
(a)Calculate the wavelength in the deep region.[2]
(b)State the frequency in the shallow region and calculate the wavelength there.[2]
(c)The waves meet the boundary at an angle. Describe what happens to their direction of travel as they enter the shallow region.[1]
Show answer
(a) 1.5 cm
λ = v/f (C1) = 18 ÷ 12 = 1.5 cm (A1)
(b) 12 Hz; 1.0 cm
frequency unchanged, 12 Hz (B1); λ = 12 ÷ 12 = 1.0 cm (B1)
(c) they change direction, bending towards the normal (refraction)
B1
Q4General wave properties · Standard · Paper 2 style · 1 mark
(a)An earthquake produces P-waves and S-waves. Which row correctly describes both types of seismic wave?[1]
Show answer
(a) A P-waves longitudinal; S-waves transverse
P-waves (primary) are longitudinal: the ground vibrates parallel to the direction of energy transfer. S-waves (secondary) are transverse: vibrations perpendicular to it. B reverses the two, the commonest error.
Q5General wave properties · Standard · Paper 4 style · 6 marks
A student shakes one end of a long rope up and down to send a transverse wave along it. In a photograph, the first crest is 0.30 m from her hand and the fourth crest is 2.10 m from her hand. The vertical distance from a crest to a trough is 16 cm. She moves her hand up and down 2.5 times per second.
(a)Calculate the wavelength of the wave.[2]
(b)State the amplitude of the wave.[1]
(c)Calculate the speed of the wave and its period.[3]
Show answer
(a) 0.60 m
3 wavelengths between 1st and 4th crests (C1): (2.10 − 0.30) ÷ 3 = 0.60 m (A1)
(b) 8.0 cm
half of crest-to-trough distance: 16 ÷ 2 = 8.0 cm (B1)
(c) speed 1.5 m/s; period 0.40 s
v = fλ = 2.5 × 0.60 (C1) = 1.5 m/s (A1); T = 1/f = 0.40 s (B1)
Q6General wave properties · Challenge · Paper 4 style · 6 marks
A long-wave radio transmitter broadcasts at a frequency of 198 kHz. Radio waves travel at 3.0 × 10⁸ m/s.
(a)Calculate the wavelength of the radio waves.[2]
(b)Describe how the amount of diffraction of a wave passing through a gap depends on the width of the gap compared with the wavelength.[2]
(c)Use your answers to explain why long-wave radio can be received in a valley between mountains in Gilgit-Baltistan, while short-wavelength signals from the same direction cannot.[2]
(b) diffraction is greatest when the gap width is about the same as the wavelength; when the gap is much wider than the wavelength there is little spreading
B1 each point
(c) long waves have a wavelength comparable with the size of hills and mountains, so they diffract significantly around them into the valley; short wavelengths diffract very little and are blocked
long wavelength similar to obstacle size → large diffraction (B1); short waves hardly diffract, so shadow region (B1)
Q7General wave properties · Challenge · Paper 6 style · 7 marks
A student investigates how the speed of water waves in a long tray depends on the depth of water. She lifts one end of the tray slightly and lets it drop, then times how long the wave takes to travel to the far end and back, a total distance of 1.80 m. Each time is an average of three readings.depth d / cm: 1.0, 2.0, 3.0, 4.0, 5.0time t / s: 5.75, 4.07, 3.32, 2.87, 2.57
(a)Calculate the wave speed v for the depths 1.0 cm and 3.0 cm. Give your answers to 2 significant figures.[2]
(b)A student suggests that the speed is directly proportional to the depth. State whether the results support this, using values from the results.[2]
(c)Suggest one difficulty in timing the wave accurately and one way of overcoming it.[2]
(d)State one variable that should be kept constant.[1]
Show answer
(a) 0.31 m/s and 0.54 m/s
v = 1.80 ÷ t: 1.80 ÷ 5.75 = 0.31 m/s (B1); 1.80 ÷ 3.32 = 0.54 m/s (B1)
(b) no: when the depth is tripled from 1.0 cm to 3.0 cm, the speed increases only from 0.31 m/s to 0.54 m/s (factor of about 1.7, not 3)
not supported (B1); supported by a correct numerical comparison (B1)
(c) difficulty: the wave is hard to see / the time is short so reaction time is significant; improvement: time several journeys up and down the tray and divide, or film the wave and use frame-by-frame playback
B1 difficulty; B1 matching improvement
(d) the length of the tray / the height through which the end is lifted / the same type of liquid (water)
B1
Q8Light: reflection & refraction · Core · Paper 4 style · 6 marks
A ray of light strikes a flat plane mirror. The angle of incidence is 35°.
(a)State the angle of reflection.[1]
(b)Calculate the angle between the reflected ray and the surface of the mirror.[1]
(c)Ayesha stands 1.5 m in front of a tall plane mirror. State the distance between Ayesha and her image.[1]
(d)Describe three properties of the image formed by a plane mirror.[3]
Show answer
(a) 35°
angle of reflection = angle of incidence (B1)
(b) 55°
90° − 35° = 55° (B1)
(c) 3.0 m
image is as far behind the mirror as the object is in front: 1.5 + 1.5 = 3.0 m (B1)
(d) virtual; upright; same size as the object; laterally inverted; same distance behind the mirror as the object is in front
1 mark each for any three
Q9Light: reflection & refraction · Core · Paper 2 style · 1 mark
(a)[1]
Show answer
(a) B it slows down and bends towards the normal
Water is optically denser than air: light travels more slowly and so bends towards the normal. A describes light leaving water into air.
Q10Light: reflection & refraction · Standard · Paper 4 style · 6 marks
A ray of light travels from air into a glass block of refractive index 1.52. The angle of incidence at the air–glass surface is 50°. The speed of light in air is 3.0 × 10⁸ m/s.
(a)Calculate the angle of refraction in the glass.[3]
(b)Calculate the speed of light in the glass.[2]
(c)State what happens to the frequency of the light as it enters the glass.[1]
Show answer
(a) 30° (30.3°)
n = sin i / sin r (C1); sin r = sin 50° ÷ 1.52 = 0.504 (C1); r = 30.3° (A1)
(b) 2.0 × 10⁸ m/s (1.97 × 10⁸ m/s)
n = c/v, so v = 3.0 × 10⁸ ÷ 1.52 (C1) = 1.97 × 10⁸ m/s (A1)
(c) it stays the same
B1
Q11Light: reflection & refraction · Standard · Paper 2 style · 1 mark
(a)The critical angle for light in a type of glass is 41.8°. What is the refractive index of the glass?[1]
Show answer
(a) C 1.50
n = 1 ÷ sin c = 1 ÷ sin 41.8° = 1.50. A is sin 41.8° itself (0.67), not its reciprocal.
Q12Light: reflection & refraction · Standard · Paper 6 style · 6 marks
A student traces rays through a rectangular glass block on paper using optics pins. She measures the angle of incidence i at the first surface and the angle of refraction r inside the block.i / °: 20, 30, 40, 50, 60r / °: 13.0, 19.5, 25.5, 30.5, 35.5
(a)Calculate the refractive index n of the glass using the result for i = 50°. Give your answer to 3 significant figures.[2]
(b)The student plots a graph of sin i (y-axis) against sin r (x-axis). Describe the graph expected and state what its gradient represents.[2]
(c)Suggest two precautions to make the ray traces as accurate as possible.[2]
Show answer
(a) 1.51
n = sin 50° ÷ sin 30.5° (C1) = 0.766 ÷ 0.508 = 1.51 (A1)
(b) a straight line through the origin; the gradient is the refractive index n
straight line through origin (B1); gradient = n (B1)
(c) place pins far apart (at least 5 cm); view the bases of the pins when lining them up; use a sharp pencil to draw thin lines; draw the normal accurately with a protractor
1 mark each for any two
Q13Light: reflection & refraction · Standard · Paper 4 style · 6 marks
The speed of light in diamond is 1.24 × 10⁸ m/s. The speed of light in air is 3.0 × 10⁸ m/s.
(a)Calculate the refractive index of diamond.[2]
(b)Calculate the critical angle for diamond.[2]
(c)Use your answer to (b) to explain why a cut diamond sparkles brightly.[2]
Show answer
(a) 2.42
n = c/v (C1) = 3.0 ÷ 1.24 = 2.42 (A1)
(b) 24.4°
sin c = 1/n (C1); c = 24.4° (A1)
(c) the critical angle is small, so light entering the diamond is very likely to strike inner faces at more than the critical angle and is totally internally reflected many times before leaving through the top
small critical angle (B1); repeated total internal reflection (B1)
Q14Light: reflection & refraction · Challenge · Paper 4 style · 7 marks
An optical fibre used for broadband internet has a glass core of refractive index 1.48. Light travels along the core by repeated total internal reflection.
(a)Calculate the critical angle for the core–air boundary.[2]
(b)A ray inside the core strikes the boundary at an angle of incidence of 60°. State and explain what happens to the ray.[2]
(c)Another ray inside the core strikes the boundary at an angle of incidence of 38°. Calculate the angle of refraction of the ray that emerges into the air.[2]
(d)State one use of optical fibres in medicine.[1]
Show answer
(a) 42.5°
sin c = 1/n (C1) = 1 ÷ 1.48, c = 42.5° (A1)
(b) it is totally internally reflected, because 60° is greater than the critical angle
TIR (B1); because angle of incidence > critical angle (B1)
(c) 65.7° (66°)
1.48 × sin 38° = sin r (C1); sin r = 0.911, r = 65.7° (A1)
(d) endoscope, to see inside the body
B1
Q15Light: reflection & refraction · Challenge · Paper 4 style · 5 marks
A ray of light strikes a plane mirror. The angle between the incident ray and the surface of the mirror is 40°.
(a)State the angle of reflection.[1]
(b)Calculate the angle between the incident ray and the reflected ray.[1]
(c)The mirror is rotated by 10° so that the angle of incidence increases. The incident ray does not move. Calculate the angle through which the reflected ray turns.[2]
(d)Explain why the image in a plane mirror is described as virtual.[1]
Show answer
(a) 50°
angle of incidence = 90° − 40° = 50°, so reflection = 50° (B1)
(b) 100°
50° + 50° = 100° (B1)
(c) 20°
new angle of incidence 60°, angle between rays 120° (C1); reflected ray turns 120° − 100° = 20° (A1)
(d) the reflected rays do not actually pass through the image; they only appear to come from it, so it cannot be formed on a screen
B1
Q16Lenses & dispersion · Core · Paper 4 style · 6 marks
A thin converging lens is used in a simple camera.
(a)Explain what is meant by the principal focus of a converging lens.[2]
(b)Define the focal length.[1]
(c)A distant tree is photographed. The object is more than twice the focal length from the lens. Describe the image formed.[3]
Show answer
(a) the point on the principal axis through which rays parallel to the principal axis pass after refraction by the lens
parallel rays to the axis (B1); converge at a point on the principal axis (B1)
(b) the distance from the centre of the lens to the principal focus
B1
(c) real, inverted, diminished (smaller than the object)
1 mark each
Q17Lenses & dispersion · Core · Paper 2 style · 1 mark
(a)[1]
Show answer
(a) D violet
Violet light has the highest frequency in the visible spectrum; glass has the largest refractive index for it, so it bends most. Red (A) bends least.
Q18Lenses & dispersion · Standard · Paper 4 style · 6 marks
An object 3.0 cm tall stands upright on the principal axis, 15 cm from a converging lens of focal length 10 cm.
(a)By drawing a scale ray diagram (or otherwise), determine the distance of the image from the lens.[3]
(b)Determine the height of the image.[1]
(c)State two other properties of the image.[2]
Show answer
(a) 30 cm on the opposite side of the lens (accept 28–32 cm)
ray parallel to axis then through F (B1); ray through centre of lens undeviated (B1); image 30 cm from lens (A1)
(b) 6.0 cm (accept 5.6–6.4 cm)
magnification 30/15 = 2, height 6.0 cm (B1)
(c) real; inverted (and enlarged)
1 mark each
Q19Lenses & dispersion · Standard · Paper 2 style · 1 mark
(a)[1]
Show answer
(a) B virtual, upright, enlarged
With the object inside the focal length the lens acts as a magnifying glass: the image is virtual, upright and enlarged on the same side as the object. A describes an object between F and 2F.
Q20Lenses & dispersion · Standard · Paper 4 style · 6 marks
When white light passes through a triangular glass prism, a band of colours can be seen on a screen.
(a)Name this effect.[1]
(b)State the seven colours of the visible spectrum in order of increasing frequency.[2]
(c)Explain why white light separates into colours in the prism.[2]
(d)Explain what is meant by monochromatic light.[1]
(c) different colours (frequencies) travel at different speeds in glass, so they have different refractive indices and are refracted through different angles
different speeds / refractive index (B1); different amounts of refraction (B1)
(d) light of a single frequency (single colour)
B1
Q21Lenses & dispersion · Challenge · Paper 4 style · 7 marks
Rashid's grandfather can see distant mountains clearly but cannot read the newspaper held at a normal reading distance. His granddaughter can read easily but cannot see the scoreboard at the far end of a cricket ground clearly.
(a)Name the sight defect of the grandfather and state where light from the newspaper is focused in his eye without glasses.[2]
(b)Name the type of lens that corrects his defect and explain how it works.[2]
(c)Name the granddaughter's defect, state the type of correcting lens and explain its effect.[3]
Show answer
(a) long sight; behind the retina
B1 each
(b) converging lens: it makes the rays converge more before they enter the eye so they focus on the retina
converging (B1); adds convergence so image moves forward onto the retina (B1)
(c) short sight; diverging lens; it spreads out the rays from distant objects so that the eye's lens focuses them on the retina instead of in front of it
short sight (B1); diverging lens (B1); rays diverged so image moves back from in front of retina onto it (B1)
Q22Electromagnetic spectrum · Core · Paper 4 style · 6 marks
(a)List the regions of the electromagnetic spectrum in order of increasing frequency, starting with radio waves.[2]
(b)State the speed of all electromagnetic waves in a vacuum.[1]
(c)Give one use each of microwaves and X-rays.[2]
(d)State one harmful effect on people of excessive exposure to ultraviolet radiation.[1]
(c) microwaves: mobile phones / satellite TV / microwave ovens; X-rays: medical imaging of bones / airport security scanners
1 mark each
(d) damage to surface cells and eyes, leading to skin cancer or eye conditions
B1
Q23Electromagnetic spectrum · Standard · Paper 4 style · 6 marks
Electromagnetic waves travel at 3.0 × 10⁸ m/s.
(a)A Wi-Fi router uses a frequency of 2.4 GHz. Calculate the wavelength.[2]
(b)An FM radio station broadcasts at 101 MHz. Calculate the wavelength.[1]
(c)A geostationary satellite is 3.6 × 10⁷ m above a ground station. Calculate the time for a microwave signal to travel from the station to the satellite.[2]
(d)Name the region of the electromagnetic spectrum used for communicating with satellites.[1]
t = d/v (C1) = 3.6 × 10⁷ ÷ 3.0 × 10⁸ = 0.12 s (A1)
(d) microwaves
B1
Q24Electromagnetic spectrum · Standard · Paper 4 style · 7 marks
(a)Describe the harmful effect on people of excessive exposure to each of: (i) microwaves, (ii) infrared, (iii) X-rays and gamma rays.[3]
(b)A radiographer in a hospital takes many X-ray images each day. Suggest two precautions she takes to reduce her own exposure.[2]
(c)State two uses of infrared radiation.[2]
Show answer
(a) (i) internal heating of body cells; (ii) skin burns; (iii) mutation or damage to cells, which can cause cancer
1 mark each
(b) stands behind a lead screen or in another room; wears a lead apron; wears a dosimeter badge to monitor exposure; limits time near the source
1 mark each for any two
(c) remote controllers; thermal imaging (e.g. night-vision or fever-screening cameras); electric grills/toasters; optical fibres; intruder alarms
1 mark each
Q25Electromagnetic spectrum · Challenge · Paper 4 style · 7 marks
Telephone calls between Karachi and Lahore are carried as digital signals along optical fibres.
(a)Describe the difference between an analogue signal and a digital signal.[2]
(b)Explain two advantages of transmitting the call as a digital signal rather than an analogue one.[4]
(c)Name the region of the electromagnetic spectrum usually used in optical fibres.[1]
Show answer
(a) an analogue signal varies continuously and can take any value; a digital signal has only a small number of values, usually two (on/off, 1/0)
B1 each
(b) digital signals can be regenerated: noise picked up along the way can be removed because the receiver only has to recognise 1s and 0s, so the quality is maintained over long distances; digital data can be transmitted at a faster rate (more information per second) and can be processed or encrypted by computers
Q26Electromagnetic spectrum · Challenge · Paper 2 style · 1 mark
(a)Which of these electromagnetic waves has the longest wavelength?[1]
Show answer
(a) D microwaves
In order of increasing wavelength: X-rays, ultraviolet, infrared, microwaves. Infrared (A) is longer than visible light but shorter than microwaves.
Q27Sound · Core · Paper 4 style · 4 marks
A student stands 85 m from the tall wall of a school building and claps once. She hears the echo 0.50 s after the clap.
(a)Calculate the speed of sound in air from these results.[2]
(b)State the approximate range of frequencies that can be heard by a healthy human ear.[1]
(c)Explain why sound cannot travel through a vacuum.[1]
Show answer
(a) 340 m/s
distance travelled = 2 × 85 = 170 m (C1); v = 170 ÷ 0.50 = 340 m/s (A1)
(b) 20 Hz to 20 000 Hz (20 kHz)
B1
(c) sound is a longitudinal wave of vibrating particles, so it needs a medium; a vacuum has no particles
B1
Q28Sound · Standard · Paper 4 style · 5 marks
Ultrasound is used to produce images of an unborn baby in a hospital in Faisalabad, and in sonar on a survey ship in the Arabian Sea.
(a)State what is meant by ultrasound.[1]
(b)A pulse of ultrasound travels at 1500 m/s through body tissue. The echo from a boundary inside the body returns 6.5 × 10⁻⁵ s after the pulse is sent. Calculate the depth of the boundary below the probe, in cm.[2]
(c)The ship's sonar receives an echo from the sea bed 2.4 s after sending a pulse. The speed of sound in sea water is 1500 m/s. Calculate the depth of the sea.[2]
Show answer
(a) sound with a frequency above 20 kHz (above the upper limit of human hearing)
B1
(b) 4.9 cm
depth = v × t ÷ 2 (C1) = 1500 × 6.5 × 10⁻⁵ ÷ 2 = 0.0488 m = 4.9 cm (A1)
(c) 1800 m
1500 × 2.4 ÷ 2 (C1) = 1800 m (A1)
Q29Sound · Standard · Paper 6 style · 6 marks
Two students measure the speed of sound on a sports field. Student A stands 150 m from student B and bangs two cymbals together. Student B starts a stopwatch when he sees the cymbals meet and stops it when he hears the sound. Times recorded: 0.48 s, 0.42 s, 0.45 s, 0.47 s.
(a)Calculate the average time.[1]
(b)Calculate the speed of sound. Give your answer to 2 significant figures.[2]
(c)Explain why the time taken for the light to reach student B can be ignored.[1]
(d)Suggest two improvements to the experiment.[2]
Show answer
(a) 0.455 s (0.46 s)
(0.48 + 0.42 + 0.45 + 0.47) ÷ 4 = 0.455 s (B1)
(b) 330 m/s
v = 150 ÷ 0.455 (C1) = 330 m/s (A1)
(c) light travels about a million times faster than sound, so its travel time over 150 m is negligible
B1
(d) use a larger distance so the time is longer and the reaction-time error is a smaller fraction; repeat more times and average; swap positions and average to cancel the effect of wind; use two microphones and an electronic timer
1 mark each for any two
Q30Sound · Challenge · Paper 4 style · 7 marks
A microphone connected to an oscilloscope picks up a steady note from a flute. The trace shows exactly 4 complete waves across 10 horizontal divisions. The time-base is set at 0.50 ms per division. The speed of sound in air is 330 m/s.
(a)Calculate the period and the frequency of the note.[3]
(b)Calculate the wavelength of the note in air.[1]
(c)The flute then plays a louder note of higher pitch. Describe two changes to the trace, with the oscilloscope settings unchanged.[2]
(d)Sound travels through air, steel and water. State the medium in which sound travels fastest and the medium in which it travels slowest.[1]
Show answer
(a) period 1.25 ms; frequency 800 Hz
10 × 0.50 = 5.0 ms for 4 waves (C1); T = 1.25 ms (A1); f = 1 ÷ 0.00125 = 800 Hz (A1)
(b) 0.41 m (0.4125 m)
λ = 330 ÷ 800 = 0.41 m (B1)
(c) the amplitude (height) of the waves increases; more waves appear across the screen (shorter wavelength on the trace)
B1 each
(d) fastest steel, slowest air
B1
Similar questions
Questions that test the same subtopic in different years, grouped so you can work on one skill at a time.
References only: find each question in its paper (official link where available, otherwise through your school).
General wave propertiesBanker137 questions · 9/9 sessions